In the spirit of Haalands explicit pipe friction factor approximation, Eq. (6.49)
Chapter 6, Problem p6.60(choose chapter or problem)
In the spirit of Haalands explicit pipe friction factor approximation, Eq. (6.49), Jeppson [20] proposed the following explicit formula: 1 1f < 22.0 log10 a /d 3.7 1 5.74 Re0.9 d b (a) Is this identical to Haalands formula with just a simple rearrangement? Explain. (b) Compare Jeppsons formula to Haalands for a few representative values of (turbulent) Red and /d and their errors compared to the Colebrook formula (6.48). Discuss briefl y
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer