In the spirit of Haalands explicit pipe friction factor approximation, Eq. (6.49)

Chapter 6, Problem p6.60

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In the spirit of Haalands explicit pipe friction factor approximation, Eq. (6.49), Jeppson [20] proposed the following explicit formula: 1 1f < 22.0 log10 a /d 3.7 1 5.74 Re0.9 d b (a) Is this identical to Haalands formula with just a simple rearrangement? Explain. (b) Compare Jeppsons formula to Haalands for a few representative values of (turbulent) Red and /d and their errors compared to the Colebrook formula (6.48). Discuss briefl y

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