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A 0.145-kg baseball pitched horizontally at 35.0 m/s

Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli ISBN: 9780130606204 3

Solution for problem 62GP Chapter 7

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli

Physics: Principles with Applications | 6th Edition

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Problem 62GP

Problem 62GP

A 0.145-kg baseball pitched horizontally at 35.0 m/s strikes a bat and is popped straight up to a height of 55.6 m. If the contact time is 1.4 ms, calculate the average force on the ball during the contact.

Step-by-Step Solution:

Solution 62GPIntroductionWe need to calculate linear acceleration first from the given data and then we can calculatethe time required by using the value of distance given.Step 1:Diameter of the pulley = 50 cmRadius r = 0.25 mMass of the pulley m = 2.0 kg 1 2 2So, its moment of inertia I = 2 × 2.0 kg × (0.25) kg.m 2I = 0.0625 kg.m …..(1)Let T be the tension on the rope 1So, T 1.5g = 1.5a ( a is linear acceleration) 1T 1 = 1.5g + 1.5a…..(2)Given that, T 2 = 10 N …..(3)Torque due to T = = 0.25 m × 10 N (from equation (3)) 2 2 2 = 2.5 N.mTorque due to tension T 1 = 0.25 m × (1.5g + 1.5a)(from equation (2)) 1Therefore, net torque = 2 1 = 2.5 N.m 0.25 m × (1.5g + 1.5a)…..(4)

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Chapter 7, Problem 62GP is Solved
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Textbook: Physics: Principles with Applications
Edition: 6
Author: Douglas C. Giancoli
ISBN: 9780130606204

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A 0.145-kg baseball pitched horizontally at 35.0 m/s