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A landscape architect represents a flower bed by a polygon with vertices (1, 0) , (4, 0)

Geometry | 1st Edition | ISBN: 9780030923456 | Authors: Rinehart, Winston Holt ISBN: 9780030923456 414

Solution for problem 7 Chapter 12

Geometry | 1st Edition

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Geometry | 1st Edition | ISBN: 9780030923456 | Authors: Rinehart, Winston Holt

Geometry | 1st Edition

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11
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Problem 7

A landscape architect represents a flower bed by a polygon with vertices (1, 0) , (4, 0) ,(4, 2) , and (1, 2) . She decides to move the flower bed to a new location by translatingit along the vector -4, -3. Draw the flower bed in its final position.

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Spencer Kociba MATH 200-005 Lecture Notes Week 6 10/24/2016 Directional Derivatives ● Definition for Directional Derivatives ○ If f(x,y) is a function and u =< u ,u > is a unit vector, then the directonal 1 2 derivative of f in the direction of u at (x ,y ) is denoted D f(x ,y ) and is given o o u o o by D f(x ,y ) = d [f(x + u s, y + u s)]|s = 0 u o o ds o 1 o 2 ○ D f(x ,y ) = lim f(o +1 ho y2+u ho−o(x ,y ) u o o h→0 h ● Notes ○ fx(o ,yo) = Duf(xo,yo) u=<1,0> ○

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Chapter 12, Problem 7 is Solved
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Textbook: Geometry
Edition: 1
Author: Rinehart, Winston Holt
ISBN: 9780030923456

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A landscape architect represents a flower bed by a polygon with vertices (1, 0) , (4, 0)