An electron with speed is traveling parallel to an
Chapter 16, Problem 62(choose chapter or problem)
An electron with speed \(v_{0}=5.32 \times 10^{6} \mathrm{~m} / \mathrm{s}\) is traveling parallel to an electric field of magnitude \(E=9.45 \times 10^{3} \mathrm{~N} / \mathrm{C}\). (a) How far will the electron travel before it stops? (b) How much time will elapse before it returns to its starting point?
Equation Transcription:
Text Transcription:
v_0=5.32 times 10^6 m/s
E=9.45 times 10^3 N/C
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