The inverse of A = eye(n) + ones(n) is A-I = eye(n) + C * ones(n). Multiply AA-I to find
Chapter 6, Problem 38(choose chapter or problem)
The inverse of A = eye(n) + ones(n) is A-I = eye(n) + C * ones(n). Multiply AA-I to find that number C (depending on n)
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