The force on a wire is a maximum of when placed between
Chapter 20, Problem 7(choose chapter or problem)
(II) The force on a wire is a maximum of \(8.50 \times 10^{-2} \mathrm{~N}\) when placed between the pole faces of a magnet. The current flows horizontally to the right and the magnetic field is vertical. The wire is observed to "jump" toward the observer when the current is turned on. (a) What type of magnetic pole is the top pole face? (b) If the pole faces have a diameter of 10.0 cm, estimate the current in the wire if the field is 0.220 T. (c) If the wire is tipped so that it makes an angle of \(10.0^{\circ}\) with the horizontal, what force will it now feel? [Hint: What length of wire will now be in the field?]
Equation Transcription:
Text Transcription:
8.50 times 10^-2 N
10.0^circ
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer