A 3.40-g bullet moves with a speed of perpendicular to the
Chapter 20, Problem 21(choose chapter or problem)
(III) A 3.40-g bullet moves with a speed of 155 m/s perpendicular to the Earth's magnetic field of \(5.00 \times 10^{-5} \mathrm{~T}\). If the bullet possesses a net charge of \(18.5 \times 10^{-9} \mathrm{C}\), by what distance will it be deflected from its path due to the Earth's magnetic field after it has traveled 1.50 km ?
Equation Transcription:
Text Transcription:
5.00 times 10^-5 T
18.5 times 10^-9 T
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