Problem 11P

The PV diagram in Fig. 15–23 shows two possible states of a system containing 1.35 moles of a monatomic ideal gas. (P1 = P2 = 455 N/m2, V1 = 2.00 m3, V2 = 8.00 m3.) (a) Draw the process which depicts an isobaric expansion from state 1 to state 2, and label this process A. (b) Find the work done by the gas and the change in internal energy of the gas in process A. (c) Draw the two-step process which depicts an isothermal expansion from state 1 to the volume V2, followed by an isovolumetric increase in temperature to state 2, and label this process B. (d) Find the change in internal energy of the gas for the two-step process B.

FIGURE 15–23

SolutionStep 1 of 2The speed of the wave is the ratio of the wavelength or the length of the wave to thetime period(time taken to complete one cycle),That is, v = T ………..1Where v is the speed , is the wavelength and T is the time period.Since frequency(number of oscillations per second) is related to time period as, f = 1 TUsing this in above equation of speed, v = f Where f is the frequency of the wave with speed v and wavelength .