Decide whether each of the matrices in Exercise 6.1.1 is diagonalizable. Give your reasoning.
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Table of Contents
1.1
Vectors
1.2
Dot Product
1.3
Hyperplanes in Rn
1.4
Systems of Linear Equations and Gaussian Elimination
1.5
The Theory of Linear Systems
1.6
Some Applications
2.1
Matrix Operations
2.2
Linear Transformations: An Introduction
2.3
Inverse Matrices
2.4
Elementary Matrices: Rows Get Equal Time
2.5
The Transpose
3.1
Subspaces of Rn
3.2
The Four Fundamental Subspaces
3.3
Linear Independence and Basis
3.4
Dimension and Its Consequences
3.5
A Graphic Example
3.6
AbstractVector Spaces
4.1
Inconsistent Systems and Projection
4.2
Orthogonal Bases
4.3
The Matrix of a Linear Transformation and the Change-of-Basis Formula
4.4
Linear Transformations on Abstract Vector Spaces
5.1
Properties of Determinants
5.2
Cofactors and Cramers Rule
5.3
Signed Area in R2 and SignedVolume in R3
6.1
The Characteristic Polynomial
6.2
Diagonalizability
6.3
Applications
6.4
The Spectral Theorem
7.1
Complex Eigenvalues and Jordan Canonical Form
7.2
Computer Graphics and Geometry
7.3
Matrix Exponentials and Differential Equations
Textbook Solutions for Linear Algebra: A Geometric Approach
Chapter 6.2 Problem 18
Question
Suppose T : V V is a linear transformation. Suppose T is diagonalizable (i.e., there is a basis for V consisting of eigenvectors of T ). Suppose, moreover, that there is a subspace W V with the property that T (W) W. Prove that there is a basis for W consisting of eigenvectors of T . (Hint: Using Exercise 3.4.17, concoct a basis for V by starting with a basis for W. Consider the matrix for T with respect to this basis. What is its characteristic polynomial?)
Solution
Step 1 of 2
It is given that,
is a linear transformation.
Also, is diagonalizable.
Suppose that there is a subspace with the property that
.
To prove that there is a basis for consisting of eigenvectors of
.
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full solution
Title
Linear Algebra: A Geometric Approach 2
Author
Ted Shifrin, Malcolm Adams
ISBN
9781429215213