Suppose T : V V is a linear transformation. Suppose T is diagonalizable (i.e., there is | StudySoup

Textbook Solutions for Linear Algebra: A Geometric Approach

Chapter 6.2 Problem 18

Question

Suppose T : V V is a linear transformation. Suppose T is diagonalizable (i.e., there is a basis for V consisting of eigenvectors of T ). Suppose, moreover, that there is a subspace W V with the property that T (W) W. Prove that there is a basis for W consisting of eigenvectors of T . (Hint: Using Exercise 3.4.17, concoct a basis for V by starting with a basis for W. Consider the matrix for T with respect to this basis. What is its characteristic polynomial?)

Solution

Step 1 of 2

It is given that,

 is a linear transformation.

Also,  is diagonalizable.

Suppose that there is a subspace  with the property that .

To prove that there is a basis for  consisting of eigenvectors of .  

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full solution

Title Linear Algebra: A Geometric Approach 2 
Author Ted Shifrin, Malcolm Adams
ISBN 9781429215213

Suppose T : V V is a linear transformation. Suppose T is diagonalizable (i.e., there is

Chapter 6.2 textbook questions

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