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Three long wires are parallel to a z axis, and each
Chapter , Problem 69(choose chapter or problem)
Three long wires are parallel to a z axis, and each carries a current of 10 A in the positive z direction.Their points of intersection with the xy plane form an equilateral triangle with sides of 50 cm, as shown in Fig. 29-78. A fourth wire (wire b) passes through the midpoint of the base of the triangle and is parallel to the other three wires. If the net magnetic force on wire a is zero, what are the (a) size and (b) direction (&z or %z) of the current in wire b?
Questions & Answers
QUESTION:
Three long wires are parallel to a z axis, and each carries a current of 10 A in the positive z direction.Their points of intersection with the xy plane form an equilateral triangle with sides of 50 cm, as shown in Fig. 29-78. A fourth wire (wire b) passes through the midpoint of the base of the triangle and is parallel to the other three wires. If the net magnetic force on wire a is zero, what are the (a) size and (b) direction (&z or %z) of the current in wire b?
ANSWER:Problem 69
Three long wires are parallel to a z axis, and each carries a current of 10 A in the positive z direction.Their points of intersection with the xy plane form an equilateral triangle with sides of 50 cm, as shown in the figure. A fourth wire (wire b) passes through the midpoint of the base of the triangle and is parallel to the other three wires. If the net magnetic force on wire a is zero, what are the (a) size and (b) direction (&z or %z) of the current in wire b?
Step by Step Solution
Step 1 of 2
a.
Take wire at the bottom as wire , wire at the bottom right as wire
Given and
By Fleming’s the right hand rule, the magnetic field (evaluated at point ‘a’) produced by wire 1 is at (measured counterclockwise from the axis,in the plane),and the field produced by wire 2 is . By symmetry we observe that only the components survive,resulting
Now use the equation …….(a). To cancel this,wire must carry current into the page( direction) of value.
and equation can be used