The Haaland formula for the friction factor isf = 0.3086{log[6.9Re + (3.7D)1.11]}2
Chapter 8, Problem 8.48(choose chapter or problem)
The Haaland formula for the friction factor isf = 0.3086{log[6.9Re + (3.7D)1.11]}2 .Compare this equation for f for D = 0.00001, 0.0001, 0.001,and 0.01 and Reynolds numbers of 104, 105, 106, and 107 with theMoody chart and decide whether it is an acceptable replacementfor the Colebrook formula.
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