The Churchill formula for the friction factor isf = 8[( 8Re)12+1(A + B)1.5]1/12,whereA =
Chapter 8, Problem 8.49(choose chapter or problem)
The Churchill formula for the friction factor isf = 8[( 8Re)12+1(A + B)1.5]1/12,whereA = {2.457 ln[( 7Re)0.9+ 3.7D]}16;B = (37,530Re )16.Compare this equation for f for both the laminar and turbulentregimes for D = 0.00001, 0.0001, 0.001, and 0.01 and Reynoldsnumbers of 10, 102, 103, 104, 105, 106, and 107 with the Moodychart and decide whether it is an acceptable replacement for theColebrook formula.
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