Solution Found!
Answer: The data for Exercise 5 were generated using the following functions. Use the
Chapter 3, Problem 7(choose chapter or problem)
The data for Exercise 5 were generated using the following functions. Use the error formula to find a bound for the error, and compare the bound to the actual error for the cases n = 1 and n = 2. a. f (x) = x ln x b. f (x) = x3 + 4.001x2 + 4.002x + 1.101 c. f (x) = x cos x 2x2 + 3x 1 d. f (x) = sin(ex 2)
Questions & Answers
QUESTION:
The data for Exercise 5 were generated using the following functions. Use the error formula to find a bound for the error, and compare the bound to the actual error for the cases n = 1 and n = 2. a. f (x) = x ln x b. f (x) = x3 + 4.001x2 + 4.002x + 1.101 c. f (x) = x cos x 2x2 + 3x 1 d. f (x) = sin(ex 2)
ANSWER:Step 1 of 8
First, let's find the error bound for the given function using the result of Theorem ,
We will need the second derivative of in case , and also the third derivative for the case when . It is simple to determine the derivatives as follows.
Let's observe the case when . On the interval , the second derivative is a positive, strictly decreasing function, therefore its maximum absolute value is at . Hence, the error bound for the approximation of is
The true error of the approximation in the solution to Exercise 5 is
Which is indeed by absolute value smaller than the bound above.