PreparED Study Materials

CHEM 111: General Chemistry 1

School: Ball State University

Number of Notes and Study Guides Available: 12

Notes

Study Guides

Videos

Volume Calculation for Acetone, Olive Oil, and Chloroform
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In this video, the presenter demonstrates the process of calculating the volume of 125g for three different liquids—Acetone, Olive oil, and Chloroform—using the formula "Volume = Mass / Density," providing step-by-step solutions for each liquid, ultimately revealing their respective volumes. This instructional video guides viewers through the calculations and showcases the outcome for each liquid's volume.

Identifying Elements, Compounds, and Mixtures
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Join us in this enlightening video where we unravel the world of chemistry. We'll examine a series of options to identify elements, compounds, and mixtures. Explore the fascinating world of matter and discover how to distinguish these fundamental concepts. Whether you're a student or simply curious about the world of chemistry, this video will help you sharpen your understanding of the building blocks of matter.

Classifying Substances: From Pure Elements to Mixtures Explained
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Classify substances into various categories: element compound homogeneous mixture and heterogeneous mixture. This video breaks down the fundamental distinctions between pure substances and mixtures illustrating with real-world examples like urine pure water a Snickers™ bar and soil. A concise guide for understanding the essence of material classification in chemistry.

Determining Ionizable H Atoms in Malonic Acid via Neutralization
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Explore the process of determining ionizable hydrogen atoms in malonic acid using its molecular formula C3H4O4 and a neutralization reaction with Sodium hydroxide. Through methodical calculations involving the given mass of malonic acid and the required volume of Sodium hydroxide for neutralization we uncover that each molecule of malonic acid contains two ionizable H atoms.

Determining Mass Percent Concentration of Solutions
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This instructional video demonstrates the process of calculating the mass percent of various solutions, using the formula "mass of solute divided by mass of solution, all multiplied by 100%." It provides step-by-step calculations for three different solutions, revealing the concentration of each solute in terms of mass percent, offering a practical understanding of quantifying solute proportions in solutions.

Protons reveal electron count in atoms. Which statement applies?
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In this video, we explore the information that knowledge of the number of protons in a neutral element's atom can provide. Options for determining neutron count, electron count, and identifying the element's name are examined, with a conclusion that it allows us to know both the number of electrons and the element's name.

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