Solution Found!
Evaluate the work done P W = f F dr = f (Fxdx Fydy) 0 0
Chapter 4, Problem 4.2(choose chapter or problem)
Evaluate the work done
\(W=\int_{O}^{P} \mathbf{F} \cdot d \mathbf{r}=\int_{O}^{P}\left(F_{x} d x+F_{y} d y\right)\)
by the two-dimensional force \(\mathbf{F}=\left(x^{2}, 2 x y\right)\) along the three paths joining the origin to the point P = (1, 1) as shown in Figure 4.24(a) and defined as follows:
(a) This path goes along the x axis to Q = (1, 0) and then straight up to P. (Divide the integral into two pieces, \(\int_{O}^{P}=\int_{O}^{Q}+\int_{Q}^{P}\)).
(b) On this path \(y=x^{2}\), and you can replace the term dy in (4.100) by dy = 2x dx and convert the whole integral into an integral over x.
(c) This path is given parametrically as \(x=t^{3}, y=t^{2}\). In this case rewrite x, y, dx, and dy in (4.100) in terms of t and dt, and convert the integral into an integral over t.
Questions & Answers
(1 Reviews)
QUESTION:
Evaluate the work done
\(W=\int_{O}^{P} \mathbf{F} \cdot d \mathbf{r}=\int_{O}^{P}\left(F_{x} d x+F_{y} d y\right)\)
by the two-dimensional force \(\mathbf{F}=\left(x^{2}, 2 x y\right)\) along the three paths joining the origin to the point P = (1, 1) as shown in Figure 4.24(a) and defined as follows:
(a) This path goes along the x axis to Q = (1, 0) and then straight up to P. (Divide the integral into two pieces, \(\int_{O}^{P}=\int_{O}^{Q}+\int_{Q}^{P}\)).
(b) On this path \(y=x^{2}\), and you can replace the term dy in (4.100) by dy = 2x dx and convert the whole integral into an integral over x.
(c) This path is given parametrically as \(x=t^{3}, y=t^{2}\). In this case rewrite x, y, dx, and dy in (4.100) in terms of t and dt, and convert the integral into an integral over t.
ANSWER:Step 1 of 4
Given data:
\(W=\int_{O}^{P} \boldsymbol{F} \cdot d \boldsymbol{r}=\int_{O}^{P}\left(F_{x} d x+F_{y} d y\right)\)
And
\(\begin{array}{l} F_{x}=x^{2} \\ F_{y}=2 x y \end{array}\)
The three paths are shown in the figure below,
Reviews
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