Let x(t) be a signal whose Fourier transform is X(jw) = 5(w) + 5(w- 7T) + 5(w- 5), and

Use the Fourier transform analysis equation (4.9) to calculate the Fourier transforms of: (a) e-2U-l)u(t- 1) (b) e- 2lt-ll Sketch and label the magnitude of each Fourier transform.

Use the Fourier transform analysis equation (4.9) to calculate the Fourier transforms of: (a) B(t + 1) + B(t- 1) (b) fr{u( -2- t) + u(t- 2)} Sketch and label the magnitude of each Fourier transform.

Determine the Fourier transform of each of the following periodic signals: (a) sin(21Tt + *) (b) 1 + cos(61rt + )

Use the Fourier transform synthesis equation (4.8) to determine the inverse Fourier transforms of: (a) X1 (jw) = 21T B(w) + 1r B(w - 41T) + 1r B(w + 41T) (b) X2(jw) = -2, 0, O:s;w:s;2 -2 ::; w < 0 lwl >2

Use the Fourier transform synthesis equation (4.8) to determine the inverse Fourier transform of X(jw) = IX(jw )lei

Given that x(t) has the Fourier transform X(jw ), express the Fourier transforms of the signals listed below in terms of X(jw ). You may find useful the Fourier transform properties listed in Table 4.1. (a) x 1 (t) = x(1 - t) + x( -1 - t) (b) x2(t) = x(3t- 6) (c) x3(t) = ;r 2 2 x(t - 1)

For each of the following Fourier transforms, use Fourier transform properties (Table 4.1) to determine whether the corresponding time-domain signal is (i) real, imaginary, or neither and (ii) even, odd, or neither. Do this without evaluating the inverse of any of the given transforms. (a) X1(jw) = u(w)- u(w- 2) (b) X2(jw) = cos(2w) sin(~) (c) X3(jw) = A(w)eiB(w), where A(w) = (sin2w)/w and B(w) = 2w + ~ (d) X(jw) = L~= 00 (~)1kl 5(w - k;)

Consider the signal ! 0, x(t) = t + ~' 1, t < -.!. 2 -.!. < t <.!. 2- - 2" t >.!. 2 (a) Use the differentiation and integration properties in Table 4.1 and the Fourier transform pair for the rectangular pulse in Table 4.2 to find a closed-form expression for X(jw ). (b) What is the Fourier transform of g(t) = x(t)- ~?

Consider the signal x(t) = { ~; + 1)/2, ltl > 1 -1 ::; t::; r (a) With the help of Tables 4.1 and 4.2, determine the closed-form expression for X(jw). (b) Take the real part of your answer to part (a), and verify that it is the Fourier transform of the even part of x(t). (c) What is the Fourier transform of the odd part of x(t)?

Given the relationships y(t) = x(t) * h(t) and g(t) = x(3t) * h(3t), and given that x(t) has Fourier transform X(jw) and h(t) has Fourier transform H(jw ), use Fourier transform properties to show that g(t) has the form g(t) = Ay(Bt). Determine the values of A and B.

Consider the Fourier transform pair -ltl ~ 2 e ~ 1 +w2" (a) Use the appropriate Fourier transform properties to find the Fourier transform of te-ltl. (b) Use the result from part (a), along with the duality property, to determine the Fourier transform of 4t Hint: See Example 4.13.

Let x(t) be a signal whose Fourier transform is X(jw) = 5(w) + 5(w- 7T) + 5(w- 5), and let h(t) = u(t) - u(t - 2). (a) Is x(t) periodic? (b) Is x(t) * h(t) periodic? (c) Can the convolution of two aperiodic signals be periodic?

Consider a signal x(t) with Fourier transform X(jw ). Suppose we are given the following facts: 1. x(t) is real and nonnegative. 2. ~- {(1 + jw )X(jw )} = Ae-2t u(t), where A is independent oft. 3. J _ 00 00 iX(jw )1 2 dw = 21T. Determine a closed-form expression for x(t).

Let x(t) be a signal with Fourier transform X(jw ). Suppose we are given the following facts: 1. x(t) is real. 2. x(t) = 0 fort ~ 0. 3. ~ J _:ooo ffie{X(jw )}eiwt dw = ltle-ltl. Determine a closed-form expression for x(t).

Consider the signal oo sin(kE:) 1T x(t) = k~oo (k*) D(t- k4 ). (a) Determine g(t) such that ( sin t) x(t) = 1Tt g(t). (b) Use the multiplication property of the Fourier transform to argue that X(jw) is periodic. Specify X(jw) over one period.

Determine whether each of the following statements is true or false. Justify your answers. (a) An odd and imaginary signal always has an odd and imaginary Fourier transform. (b) The convolution of an odd Fourier transform with an even Fourier transform is always odd.

Find the impulse response of a system with the frequency response H(jw) = (sin2 (3w )) cos w w2

Consider a causal LTI system with frequency response H(jw) = . 1 3 JW + For a particular input x(t) this system is observed to produce the output y(t) = e- 3tu(t)-e-4tu(t). Determine x(t).

Compute the Fourier transform of each of the following signals: (a) [e-at cos wot]u(t), a > 0 (b) e-31tl sin 2t (c) x(t) = { 1 +cos 7T't, lltll :::; 1 (d) 2:~-o ak o(t- kT), Ia I < 1 0, t > 1 - (e) [te-2tsin4t]u(t) (f) [sin7Tt][sin27T(t-l)] 1Tt 1T(t-l) (g) x(t) as shown in Figure P4.21(a) (i) x(t) = { 1 - t 2 , 0 < t ~ 1 0, otherwise (h) x(t) as shown in Figure P4.21(b) (j) """"+oo -lt-2nl Ln=-ao e

Determine the continuous-time signal corresponding to each of the following transforms. (a) X(jw) = 2sin[3(w-27T)] (w-27T) (b) X(jw) = cos(4w + 7r/3) (c) X(jw) as given by the magnitude and phase plots of Figure P4.22(a) (d) X(jw) = 2[o(w - 1) - o(w + 1)] + 3[o(w - 27r) + o(w + 27r)] (e) X(jw) as in Figure P4.22(b)

Consider the signal { -t 0 < t < 1 () e ' - - x0 t = 0, elsewhere 339 Determine the Fourier transform of each of the signals shown in Figure P4.23. You should be able to do this by explicitly evaluating only the transform of x0(t) and then using properties of the Fourier transform.

(a) Determine which, if any, of the real signals depicted in Figure P4.24 have Fourier transforms that satisfy each of the following conditions: (1) CR-e{X(jw)} = 0 (2) dm{X(jw )} = 0 (3) There exists a real a such that ejaw X(jw) is real (4) J_::'ooX(jw)dw = 0 (5) J_::'oowX(jw)dw = 0 (6) X(jw) is periodic (b) Construct a signal that has properties (1), (4), and (5) and does not have the others.

Let X(jw) denote the Fourier transform of the signal x(t) depicted in Figure P4.25. (a) Find 1:X(jw ). (b) Find X(jO). (c) Findf:oox(jw)dw. (d) Evaluate J :oo X(jw ) 2 s:w ejlw dw. (e) Evaluate J :oo iX(Jw )1 2 dw. (f) Sketch the inverse Fourier transform of CRe{X(jw )}. Note: You should perform all these calculations without explicitly evaluating X(jw ).

(a) Compute the convolution of each of the following pairs of signals x(t) and h(t) by calculating X(jw) and H(jw ), using the convolution property, and inverse transforming. (i) x(t) = te-lt u(t), h(t) = e-4t u(t) (ii) x(t) = te-lt u(t), h(t) = te-4t u(t) (iii) x(t) = e-tu(t), h(t) = etu(-t) (b) Suppose that x(t) = e-(t-l)u(t- 2) and h(t) is as depicted in Figure P4.26. Verify the convolution property for this pair of signals by showing that the Fourier transform of y(t) = x(t) * h(t) equals H(jw )X(jw ).

Consider the signals x(t) = u(t - 1) - 2u(t- 2) + u(t - 3) and 00 i(t) = L, x(t- kT), where T > 0. Let ak denote the Fourier series coefficients of i(t), and let X(jw) denote the Fourier transform of x(t). (a) Determine a closed-form expression for X(jw ). (b) Determine an expression for the Fourier coefficients ak and verify that ak = tx(i2;k ).

(a) Let x(t) have the Fourier transform X(jw ), and let p(t) be periodic with fundamental frequency wo and Fourier series representation +oo p(t) = 2.: anejnwot. n=-oo Determine an expression for the Fourier transform of y(t) = x(t)p(t). (P4.28-1) (b) Suppose that X(jw) is as depicted in Figure P4.28(a). Sketch the spectrum of y(t) in eq. (P4.28-1) for each of the following choices of p(t): (i) p(t) = cos(t/2) (ii) p(t) = cost (iii) p(t) = cos 2t (iv) p(t) = (sin t)(sin 2t) (v) p(t) = cos 2t- cost (vi) p(t) = 2:;: _00 8(t- 1Tn) (vii) p(t) = 2:;: _00 8(t - 27Tn) (viii) p(t) = 2:;: _00 8(t - 41Tn) (ix) p(t) = 2:;: -oo 8(t- 27Tn) - i 2:;: _00 8(t- 1Tn) (x) p(t) = the periodic square wave shown in Figure P4.28(b ).

A real-valued continuous-time function x(t) has a Fourier transform X(jw) whose magnitude and phase are as illustrated in Figure P4.29(a). The functions Xa(t), xb(t), Xc(t), and xd(t) have Fourier transforms whose magnitudes are identical to X(jw ), but whose phase functions differ, as shown in Figures P4.29(b)-(e). The phase functions 1:.Xa(jw) and 1:.Xb(jw) are formed by adding a linear phase to 1:.X(jw ). The function 1:Xc(jw) is formed by reflecting 1:X(jw) about w = 0, and 1:Xd(jw) is obtained by a combination of a reflection and an addition of a linear phase. Using the properties of Fourier transforms, determine the expressions for xa(t), xb(t), Xc(t), and xd(t) in terms of x(t)

(a) Show that the three LTI systems with impulse responses h1 (t) = u(t), h2(t) = -28(t) + 5e-2tu(t), and all have the same response to x(t) = cost. (b) Find the impulse response of another LTI system with the same response to cost. This problem illustrates the fact that the response to cos t cannot be used to specify an LTI system uniquely.

Consider an LTI system S with impulse response h(t) = sin(4(t - 1)). 7T(t - 1) Determine the output of S for each of the following inputs: (a) x1 (t) = cos(6t + ~) (b) x2(t) = 2:;= (~)k sin(3kt) (c) X (t) = sin(4(t+ I)) 3 7T(t+ 1) (d) X4(t) = cin2t)2

The input and the output of a stable and causal L TI system are related by the differential equation d2y(t) 6dy(t) 8 ( ) - 2 ( ) --+ --+ yt- xt dt2 dt (a) Find the impulse response of this system. (b) What is the response of this system if x(t) = te-2t u(t)? (c) Repeat part (a) for the stable and causal LTI system described by the equation d 2 y(t) r;:;. 2 dy(t) ( ) = 2 d 2 x(t) _ 2 ( ) dt2 + .y L dt + y t dt2 X t

A causal and stable LTI system S has the frequency response . jw +4 H(jw)=6 2 s. -w + J (a) Determine a differential equation relating the input x(t) and output y(t) of S. (b) Determine the impulse response h(t) of S. (c) What is the output of S when the input is x(t) = e-4tu(t)-te-4tu(t)?

In this problem, we provide examples of the effects of nonlinear changes in phase. (a) Consider the continuous-time LTI system with frequency response H( w) = a- jw J + . ' a JW where a> 0. What is the magnitude of H(jw )? What is

Consider an LTI system whose response to the input x(t) = [e-t + e- 3t]u(t) is y(t) = [2e-t- 2e-4t]u(t). (a) Find the frequency response of this system. (b) Determine the system's impulse response. (c) Find the differential equation relating the input and the output of this system.

Consider the signal x(t) in Figure P4.37. (a) Find the Fourier transform X(jw) of x(t). (b) Sketch the signal 00 x(t) = x(t) * L o(t - 4k). k= -00 (c) Find another signal g(t) such that g(t) is not the same as x(t) and 00 x(t) = g(t) * L o(t- 4k). (d) Argue that, although G(jw) is different from X(jw), G(jn;k) = X(jn;k) for all integers k. You should not explicitly evaluate G(jw) to answer this question.

Let x(t) be any signal with Fourier transform X(jw ). The frequency-shift property of the Fourier transform may be stated as . ~ e1wot x(t) ~ X(j(w - wo)). (a) Prove the frequency-shift property by applying the frequency shift to the analysis equation X(jw) = r~ x(t)e- Jwt dt. (b) Prove the frequency-shift property by utilizing the Fourier transform of eiwot in conjunction with the multiplication property of the Fourier transform.

Suppose that a signal x(t) has Fourier transform X(jw ). Now consider another signal g(t) whose shape is the same as the shape of X(jw ); that is, g(t) = X(jt). (a) Show that the Fourier transform G(jw) of g(t) has the same shape as 21Tx( -t); that is, show that G(jw) = 21Tx(-w). (b) Using the fact that g:{o(t + B)} = efBw in conjunction with the result from part (a), show that g:{ejBt} = 21T o(w - B).

In this problem, we derive the multiplication property ofthe continuous-time Fourier transform. Let x(t) and y(t) be two continuous-time signals with Fourier transforms X(jw) and Y(jc.q ), respectively. Also, let g(t) denote the inverse Fourier transform of ~ {X(jw) * Y(jw )}. (a) Show that 1 f +oo [ 1 f +oo . ] g(t) = 2 7T -oo X(j8) 2 7T -oo Y(j(w - O))eJwt dw dO. (b) Show that - Y(j(w - 8))e1wt dw = el8t y(t). 1 f +oo . . 27T -00 (c) Combine the results of parts (a) and (b) to conclude that g(t) = x(t)y(t).

Let g1 (t) = {[cos(wot)]x(t)} * h(t) and g2(t) = {[sin(wot)]x(t)} * h(t), where 00 x(t) = L akejkiOOt k= -DO is a real-valued periodic signal and h(t) is the impulse response of a stable LTI system. (a) Specify a value for w 0 and any necessary constraints on H(jw) to ensure that g1 (t) = (Jl.e{as} and (b) Give an example of h(t) such that H(jw) satisfies the constraints you specified in part (a).

Let 2 sint g(t) = x(t) cos t * -. 7Tt Assuming that x(t) is real and X(jw) = 0 for lwl 2: 1, show that there exists an LTI system S such that s x(t) ~ g(t).

The output y(t) of a causal LTI system is related to the input x(t) by the equation dy(t) J +oc -d- + lOy(t) = x( r)z(t- r) dr - x(t), f -oc where z(t) = e-t u(t) + 3 o(t). (a) Find the frequency response H(jw) = Y(jw )IX(jw) of this system. (b) Determine the impulse response of the system.

In the discussion in Section 4.3.7 ofParseval's relation for continuous-time signals, we saw that ---1 a 1- 0 J +oc 1 J +oc -oc lx(t)l2 dt = 2 1T -oo IX(jw )1 2 dw. This says that the total energy of the signal can be obtained by integrating IX(jw )1 2 over all frequencies. Now consider a real-valued signal x(t) processed by the ideal bandpass filter H(jw) shown in Figure P4.45. Express the energy in the output signal y(t) as an integration over frequency of IX(Jw )1 2 For~ sufficiently small so that IX(Jw )I is approximately constant over a frequency interval of width~. show that the energy in the output y(t) of the bandpass filter is approximately proportional to ~IX(Jwo)l On the basis of the foregoing result, ~IX(jw )1 2 is proportional to the energy in the signal in a bandwidth~ around the frequency w0 For this reason, IX(jw )1 2 is often referred to as the energy-density spectrum of the signal x(t).

In Section 4.5 .1, we discussed the use of amplitude modulation with a complex exponential carrier to implement a bandpass filter. The specific system was shown in Figure 4.26, and if only the real part of f(t) is retained, the equivalent bandpass filter is that shown in Figure 4.30. In Figure P4.46, we indicate an implementation of a bandpass filter using sinusoidal modulation and lowpass filters. Show that the output y(t) of the system is identical to that which would be obtained by retaining only CRe{f(t)} in Figure 4.26.

An important property of the frequency response H(jw) of a continuous-time LTI system with a real, causal impulse response h(t) is that H(jw) is completely specified by its real part, (Jl.e{H(jw )}. The current problem is concerned with deriving and examining some of the implications of this property, which is generally referred to as real-part sufficiency. (a) Prove the property of real-part sufficiency by examining the signal he(t), which is the even part of h(t). What is the Fourier transform of he(t)? Indicate how h(t) can be recovered from he(t). (b) If the real part of the frequency response of a causal system is (Jl.e{H(jw )} = cos w, what is h(t)? (c) Show that h(t) can be recovered from h 0 (t), the odd part of h(t), for every value of t except t = 0. Note that if h(t) does not contain any singularities [o(t), u1 (t), u2(t), etc.] at t = 0, then the frequency response J +oc H(jw) = -oc h(t)e- jwt dt will not change if h(t) is set to some arbitrary finite value at the single point t = 0. Thus, in this case, show that H(jw) is also completely specified by its imaginary part.

Let us consider a system with a real and causal impulse response h(t) that does not have any singularities at t = 0. In Problem 4.47, we saw that either the real or the imaginary part of H(jw) completely determines H(jw ). In this problem we derive an explicit relationship between HR(jw) and H1(jw ), the real and imaginary parts of H(jw). (a) To begin, note that since h(t) is causal, h(t) = h(t)u(t), (P4.48-l) except perhaps at t = 0. Now, since h(t) contains no singularities at t = 0, the Fourier transforms of both sides of eq. (P4.48-l) must be identical. Use this fact, together with the multiplication property, to show that H( . ) - 1 J+x H(j'YJ)d JW - -.- --- 'YJ. j7T -X w- 'YJ (P4.48-2) Use eq. (P4.48-2) to determine an expression for HR(jw) in terms of H1(jw) and one for H1(jw) in terms of HR(jw ). (b) The operation ( ) _ 1 J +x X( T) d yt-- --T 7T -X t- T (P4.48-3) is called the Hilbert transform. We have just seen that the real and imaginary parts of the transform of a real, causal impulse response h(t) can be determined from one another using the Hilbert transform. Now considereq. (P4.48-3), and regard y(t) as the output of an LTI system with input x(t). Show that the frequency response of this system is H( . ) = { - j, w > 0 JW . < o ], w (c) What is the Hilbert transform of the signal x(t) = cos 3t?

Let H(jw) be the frequency response of a continuous-time LTI system, and suppose that H(jw) is real, even, and positive. Also, assume that max{H(jw )} = H(O). w (a) Show that: (i) The impulse response, h(t), is real. (ii) max{ih(t)i} = h(O). Hint: If f(t. w) is a complex function of two variables, then (b) One important concept in system analysis is the bandwidth of an LTI system. There are many different mathematical ways in which to define bandwidth, but they are related to the qualitative and intuitive idea that a system with frequency response G(jw) essentially "stops" signals of the form eiwt for values of w where G(jw) vanishes or is small and "passes" those complex exponentials in the band of frequency where G(jw) is not small. The width of this band is the bandwidth. These ideas will be made much clearer in Chapter 6, but for now we will consider a special definition of bandwidth for those systems with frequency responses that have the properties specified previously for H(jw ). Specifically, one definition of the bandwidth Bw of such a system is the width of the rectangle of height H(jO) that has an area equal to the area under H(jw ). This is illustrated in Figure P4.49(a). Note that since H(jO) = maxw H(jw ), the frequencies within the band indicated in the figure are those for which H (jw) is largest. The exact choice of the width in the figure is, of course, a bit arbitrary, but we have chosen one definition that allows us to compare different systems and to make precise a very important relationship between time and frequency. What is the bandwidth of the system with frequency response H(jw) H(O) H(jw) . { = 1, 0, lwl < w? lwi>W. (c) Find an expression for the bandwidth Bw in terms of H(jw ). (d) Let s(t) denote the step response of the system set out in part (a). An important measure of the speed of response of a system is the rise time, which, like the bandwidth, has a qualitative definition, leading to many possible mathematical definitions, one of which we will use. Intuitively, the rise time of a system is a measure of how fast the step response rises from zero to its final value, s(oo) = lim s(t). (-H:IJ Thus, the smaller the rise time, the faster is the response of the system. For the system under consideration in this problem, we will define the rise time as s(oo) tr = h(O) Since s' (t) = h(t), and also because of the property that h(O) = maxt h(t), tr is the time it would take to go from zero to s( oo) while maintaining the maximum rate of change of s(t). This is illustrated in Figure P4.49(b ). Find an expression for tr in terms of H(jw ). s(t) (b) Figure P4.49b (e) Combine the results of parts (c) and (d) to show that Bwtr = 27r. (P4.49-l) Thus, we cannot independently specify both the rise time and the bandwidth of our system. For example, eq. (P4.49-l) implies that, if we want a fast system (tr small), the system must have a large bandwidth. This is a fundamental trade-off that is of central importance in many problems of system design.

(a) Consider two LTI systems with impulse responses h(t) and g(t), respectively, and suppose that these systems are inverses of one another. Suppose also that the systems have frequency responses denoted by H(jw) and G(jw ), respectively. What is the relationship between H(jw) and G(jw )? (b) Consider the continuous-time LTI system with frequency response H(jw) = { 1 0, 2 < iwl < 3 otherwise (i) Is it possible to find an input x(t) to this system such that the output is as depicted in Figure P4.50? If so, find x(t). If not, explain why not. (ii) Is this system invertible? Explain your answer. (c) Consider an auditorium with an echo problem. As discussed in Problem 2.64, we can model the acoustics of the auditorium as an LTI system with an impulse response consisting of an impulse train, with the kth impulse in the train corresponding to the kth echo. Suppose that in this particular case the impulse response is h(t) = L e-kT 8(t- kT), k=O where the factor e-kT represents the attenuation of the kth echo. In order to make a high-quality recording from the stage, the effect of the echoes must be removed by performing some processing of the sounds sensed by the recording equipment. In Problem 2.64, we used convolutional techniques to consider one example of the design of such a processor (for a different acoustic model). In the current problem, we will use frequency-domain techniques. Specifically, let G(jw) denote the frequency response of the LTI system to be used to process the sensed acoustic signal. Choose G(jw) so that the echoes are completely removed and the resulting signal is a faithful reproduction of the original stage sounds. (d) Find the differential equation for the inverse of the system with impulse response h(t) = 2 O(t) + UJ (t). (e) Consider the LTI system initially at rest and described by the differential equation d 2y(t) 6 dy(t) 9 ( ) _ d 2 x(t) 3 dx(t) 2 ( ) d t2 + d t + y t - ~ + ----;[( + X t . The inverse of this system is also initially at rest and described by a differential equation. Find the differential equation describing the inverse, and find the impulse responses h(t) and g(t) of the original system and its inverse.

Inverse systems frequently find application in problems involving imperfect measuring devices. For example, consider a device for measuring the temperature of a liquid. It is often reasonable to model such a device as an LTI system that, because of the response characteristics of the measuring element (e.g., the mercury in athermometer), does not respond instantaneously to temperature changes. In particular, assume that the response of this device to a unit step in temperature is s(t) = (1 - e -r12 )u(t). (P4.52-1) (a) Design a compensatory system that, when provided with the output of the measuring device, produces an output equal to the instantaneous temperature of the liquid. (b) One of the problems that often arises in using inverse systems as compensators for measuring devices is that gross inaccuracies in the indicated temperature may occur if the actual output of the measuring device produces errors due to small, erratic phenomena in the device. Since there always are such sources of error in real systems, one must take them into account. To illustrate this, consider a measuring device whose overall output can be modeled as the sum of the response of the measuring device characterized by eq. (P4.52-1) and an interfering "noise" signal n(t). Such a model is depicted in Figure P4.52(a), where we have also included the inverse system of part (a), which now has as its input the overall output of the measuring device. Suppose that n(t) = sin wt. What is the contribution of n(t) to the output of the inverse system, and how does this output change as w is increased? (c) The issue raised in part (b) is an important one in many applications of LTI system analysis. Specifically, we are confronted with the fundamental tradeoff between the speed of response of the system and the ability of the system to attenuate high-frequency interference. In part (b) we saw that this tradeoff implied that, by attempting to speed up the response of a measuring device (by means of an inverse system), we produced a system that would also amplify corrupting sinusoidal signals. To illustrate this concept further, consider a measuring device that responds instantaneously to changes in temperature, but that also is corrupted by noise. The response of such a system can be modeled, as depicted in Figure P4.52(b ), as the sum of the response of a perfect measuring qevice and a corrupting signal n(t). Suppose that we wish to design a compensatory system that will slow down the response to actual temperature variations, but also will attenuate the noise n(t). Let the impulse response of this system be h(t) = ae -at u(t). Choose a so that the overall system of Figure P4.52(b) responds as quickly as possible to a step change in temperature, subject to the constraint that the amplitude of the portion of the output due to the noise n(t) = sin 6t is no larger than 114.

As mentioned in the text, the techniques of Fourier analysis can be extended to signals having two independent variables. As their one-dimensional counterparts do in some applications, these techniques play an important role in other applications, such as image processing. In this problem, we introduce some of the elementary ideas of two-dimensional Fourier analysis. Let x(t1, t2) be a signal that depends upon two independent variables t 1 and t2. The two-dimensional Fourier transform of x(t1, t2) is defined as X(jw,, jw2) = L+: L+xx x(t,, t2)e-j(w,t, +w,t,) dt, dt2. (a) Show that this double integral can be performed as two successive onedimensional Fourier transforms, first in t 1 with t2 regarded as fixed and then in t2. (b) Use the result of part (a) to determine the inverse transform-that is, an expression for x(tJ, t2) in terms of X(jw1, jw2). (c) Determine the two-dimensional Fourier transforms of the following signals: (i) x(t1, t2) = e-t1 +2t2 u(t1 - 1)u(2 - t2) { e-1t~l-lt2l, if -1 < t1 ::; 1 and -1 ::; t2 ::; 1 (n) x(t1, t2) = O, otherwise (iii) x(t1 , t2 ) = { 0 e-lt1 Ht2 1, ifhO ::; .t1 ::; 1 or 0 ::; t2 ::; 1 (or both) , ot erw1se (iv) x(t1, t2) as depicted in Figure P4.53. (v) e-ltl +t2l-lt1-t2l -1 -1 x(t1, t2) = 1 in shaded area and 0 outside Figure P4.53 (d) Determine the signal x(t1, t2) whose two-dimensional Fourier transform is X(jw1, jw2) = 4 ~ l>(w2- 2wJ). + )WJ (e) Let x(t1, t2) and h(t1, t2) be two signals with two-dimensional Fourier transforms X(jw 1, jw2) and H(jw1, jw2), respectively. Determine the transforms of the following signals in terms of X(jw 1, jw2) and H(jw 1, jw2): (i) x(t1 - T1, t2 - T2) (ii) x(at1, bt2) (iii) y(tJ, t2) = J_+00 00 J_+00 00 X(T], T2)h(t1 - T], f2- T2)dT1 d T2