Dr. Susan Benner is an industrial psychologist. She is currently studying stress among

Chapter 0, Problem 45

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QUESTION:

Dr. Susan Benner is an industrial psychologist. She is currently studying stress among executives of Internet companies. She has developed a questionnaire that she believes measures stress. A score above 80 indicates stress at a dangerous level. A random sample of 15 executives revealed the following stress level scores.

\(\begin{array}{|lllllllllllllll|}
\hline 94 & 78 & 83 & 90 & 78 & 99 & 97 & 90 & 97 & 90 & 93 & 94 & 100 & 75 & 84 \\
\hline
\end{array}\)

a. Find the mean stress level for this sample. What is the point estimate of the population mean?

b. Construct a 95 percent confidence level for the population mean.

c. Is it reasonable to conclude that Internet executives have a mean stress level in the dangerous level, according to Dr. Benner’s test?

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QUESTION:

Dr. Susan Benner is an industrial psychologist. She is currently studying stress among executives of Internet companies. She has developed a questionnaire that she believes measures stress. A score above 80 indicates stress at a dangerous level. A random sample of 15 executives revealed the following stress level scores.

\(\begin{array}{|lllllllllllllll|}
\hline 94 & 78 & 83 & 90 & 78 & 99 & 97 & 90 & 97 & 90 & 93 & 94 & 100 & 75 & 84 \\
\hline
\end{array}\)

a. Find the mean stress level for this sample. What is the point estimate of the population mean?

b. Construct a 95 percent confidence level for the population mean.

c. Is it reasonable to conclude that Internet executives have a mean stress level in the dangerous level, according to Dr. Benner’s test?

ANSWER:

Step 1 of 3

a)

 The value of the population mean is:

\(\begin{array}{l} =\frac{94+78+83+90+78+99+97+90+97+90+93+94+100+75+84}{15} \\ =89.4667 \end{array}\)

The value of the population mean is,\(\mu=89.4667\).

Standard deviation, \(\sigma=8.078779\) and Sample Size (n) = 15

Point of estimate \(=80-89.4667=9.4667\)

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