The CrunchIt! output in Figure 23.4gives 2 degrees of freedom for the table in Exercise
Chapter 0, Problem 23.12(choose chapter or problem)
The CrunchIt! output in Figure 23.4gives 2 degrees of freedom for the table in Exercise 23.2.(a) Verify that this is correct.(b) The computer gives the value of the chi-square statistic as X2 = 7.638.Between what two entries in Table E does this value lie? What does the table tellyou about the P-value?(c) What is the mean value of the statistic X2 if the null hypothesis is true? Howdoes the observed value of X2 compare with this mean?
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