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Multiple choice: Select the best answer for Exercises 101 to 105. Joe reads that 1 out

Chapter 6, Problem 101

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QUESTION:

Joe reads that 1 out of 4 eggs contains salmonella bacteria. So he never uses more than 3 eggs in cooking. If eggs do or don't contain salmonella independently of each other, the number of contaminated eggs when Joe uses 3 chosen at random has the following distribution:

(a) binomial; n = 4 and p = 1/4

(b) binomial; n = 3 and p = 1/4

(c) binomial; n = 3 and p = 1/3

(d) geometric; p = 1/4

(e) geometric; p = 1/3

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QUESTION:

Joe reads that 1 out of 4 eggs contains salmonella bacteria. So he never uses more than 3 eggs in cooking. If eggs do or don't contain salmonella independently of each other, the number of contaminated eggs when Joe uses 3 chosen at random has the following distribution:

(a) binomial; n = 4 and p = 1/4

(b) binomial; n = 3 and p = 1/4

(c) binomial; n = 3 and p = 1/3

(d) geometric; p = 1/4

(e) geometric; p = 1/3

ANSWER:

Step 1 of 2

Probability that eggs contains salmonella bacteria,

X = the number of contaminated eggs when Joe uses 3 chosen at random

We have determine the type of distribution:

 

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