Solved: How many grams of KOH are present in 35.0 mL of a

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Here we have to calculate the mass of KOH in grams present in 35.0 mL of a 5.50 M solution

Given:

Volume of solution = 35.0  mL

Molarity = 5.50 M

In order to calculate the mass of KOH in gram we have to find out its number of moles.

It is known that,

\(\text { Molarity }=\frac{\text { moles of solute }(\mathrm{KOH})}{\text { Volume of solution }(L)}\)

\(5.50 \mathrm{M}=\frac{\text { moles of solute }(\mathrm{KOH})}{35.0 \mathrm{~mL} \times\left(\frac{1 L}{103 \mathrm{~mL}}\right)}\)

Moles of KOH  = 0.1925  moles