Solution Found!
?Prove the statement using the \(\varepsilon, \delta\), definition of a limit. \(\lim
Chapter 2, Problem 22(choose chapter or problem)
QUESTION:
Prove the statement using the \(\varepsilon, \delta\), definition of a limit.
\(\lim _{x \rightarrow-1.5} \frac{9-4 x^{2}}{3+2 x}=6\)
Questions & Answers
QUESTION:
Prove the statement using the \(\varepsilon, \delta\), definition of a limit.
\(\lim _{x \rightarrow-1.5} \frac{9-4 x^{2}}{3+2 x}=6\)
ANSWER:Step 1 of 3
Given:
The limit function is,
\(\lim _{x \rightarrow-1.5} \frac{9-4 x^{2}}{3+2 x}=6\)
The aim is to show that the given statement is true using \(\varepsilon-\delta\) definition of limit.
The means we will show that, for \(\varepsilon>0\) there is the number \(\delta>0\) such that, if \(0<|x-a|<\delta\) then \(|f(x)-L|<\varepsilon\).