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Breaking Down Mixtures: Finding Mass Percent of Sodium Compounds

Chapter 3, Problem 3.122

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QUESTION:

A mixture of NaBr and \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) contains 29.96 percent Na by mass. Calculate the percent by mass of each compound in the mixture.

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Breaking Down Mixtures: Finding Mass Percent of Sodium Compounds
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Uncover the method to determine mass percentages of Sodium Bromide and Sodium Sulfate in a mixture using the given Sodium content. Walk through a step-by-step calculation leveraging molar masses to derive the composition. Discover the resulting mass percentages: 23.85% for Sodium Bromide and 76.15% for Sodium Sulfate

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Questions & Answers

QUESTION:

A mixture of NaBr and \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) contains 29.96 percent Na by mass. Calculate the percent by mass of each compound in the mixture.

ANSWER:

Step 1 of 3

The goal of the problem is to calculate the percent by mass of each compound in the mixture.

Given:

Mass of Na = 29.96 %

Let’s consider there is 100 g of the compound. So, there is 29.96 g of Na. Let ‘x’ be the mass of NaBr, and 100 - x be the mass of \(\mathrm{Na}_{2} \mathrm{SO}_{4}\).

This amount of Na is given is the mass of Na in NaBr and the mass of Na in \(\mathrm{Na}_{2} \mathrm{SO}_{4}\). That is:

29.96 g Na = mass of Na in NaBr + mass of Na in \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) 

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