?Find the points on the ellipse \(4 x^{2}+y^{2}=4\) that are farthest away from the

Chapter 4, Problem 27

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QUESTION:

Find the points on the ellipse \(4 x^{2}+y^{2}=4\) that are farthest away from the point (1, 0).

Questions & Answers

QUESTION:

Find the points on the ellipse \(4 x^{2}+y^{2}=4\) that are farthest away from the point (1, 0).

ANSWER:

Step 1 of 3

It is given that the points lie on the ellipse,

\(4 x^{2}+y^{2}=4\).

And the point is \((1,0)\).

It is known that,

The distance between two points is determined using the formula,

\(d=\sqrt{\left(x_{1}-x_{2}\right)^{2}+\left(y_{1}-y_{2}\right)^{2}} .\).

To find the farthest points that lies on the ellipse.

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