?Which of the following inequalities can be used to show that \(\sum_{n=1}^{\infty} n

Chapter 10, Problem 6

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QUESTION:

Which of the following inequalities can be used to show that \(\sum_{n=1}^{\infty} n /\left(n^{2}+1\right)\) diverges?

(a)\(\frac{n}{n^{2+1}} \geq \frac{1}{n^{2}+1}\)                    (b) \(\frac{n}{n^{2+1}} \leq \frac{1}{n}\)

(c)  \(\frac{n}{n^{2+1}} \geq \frac{1}{2 n}\)

Equation Transcription:

Text Transcription:

sum _n=1^infinity n/(n^2 + 1)

n/n^2 + 1 > or = 1/n^2 + 1

n/n^2 + 1 < or = 1/n

n/n^2 + 1 > or = 1/2n

Questions & Answers

QUESTION:

Which of the following inequalities can be used to show that \(\sum_{n=1}^{\infty} n /\left(n^{2}+1\right)\) diverges?

(a)\(\frac{n}{n^{2+1}} \geq \frac{1}{n^{2}+1}\)                    (b) \(\frac{n}{n^{2+1}} \leq \frac{1}{n}\)

(c)  \(\frac{n}{n^{2+1}} \geq \frac{1}{2 n}\)

Equation Transcription:

Text Transcription:

sum _n=1^infinity n/(n^2 + 1)

n/n^2 + 1 > or = 1/n^2 + 1

n/n^2 + 1 < or = 1/n

n/n^2 + 1 > or = 1/2n

ANSWER:

Step 1 of 3

(a)  is convergent by Limit Comparison Test with

We cannot compare a given series with a known convergent series to prove its divergence.

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