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Answer: A gas evolved during the fermentation of glucose

Chapter 5, Problem 38P

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QUESTION:

A gas evolved during the fermentation of glucose (wine making) has a volume of 0.78 L at 20.1°C and 1.00 atm. What was the volume of this gas at the fermentation temperature of 36.5°C and 1.00 atm pressure?

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QUESTION:

A gas evolved during the fermentation of glucose (wine making) has a volume of 0.78 L at 20.1°C and 1.00 atm. What was the volume of this gas at the fermentation temperature of 36.5°C and 1.00 atm pressure?

ANSWER:

Step 1 of 2

The goal of the problem is to calculate the volume of the gas at the fermentation temperature of 36.5°C and 1.00 atm pressure.

Given:

\(T_1\) = 20.1°C = 20 + 273 = 293 K

\(P_1\) = 1.00 atm

\(T_2\) = 36.5°C = 36.5 + 273 = 309.5 K

\(P_2\) = 1.00 atm

\(V_1\) = 0.78 L

\(V_2\) = ?

 

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