Solution Found!
Answer: A gas evolved during the fermentation of glucose
Chapter 5, Problem 38P(choose chapter or problem)
A gas evolved during the fermentation of glucose (wine making) has a volume of 0.78 L at 20.1°C and 1.00 atm. What was the volume of this gas at the fermentation temperature of 36.5°C and 1.00 atm pressure?
Questions & Answers
QUESTION:
A gas evolved during the fermentation of glucose (wine making) has a volume of 0.78 L at 20.1°C and 1.00 atm. What was the volume of this gas at the fermentation temperature of 36.5°C and 1.00 atm pressure?
ANSWER:Step 1 of 2
The goal of the problem is to calculate the volume of the gas at the fermentation temperature of 36.5°C and 1.00 atm pressure.
Given:
\(T_1\) = 20.1°C = 20 + 273 = 293 K
\(P_1\) = 1.00 atm
\(T_2\) = 36.5°C = 36.5 + 273 = 309.5 K
\(P_2\) = 1.00 atm
\(V_1\) = 0.78 L
\(V_2\) = ?