Let the vector space \(\mathrm{P} 4\) have the evaluation inner product at the points \(-2,-1,0,1,2\) and let \(p=p(x)=x+x^{3}\) \(\text { and } q=q(x)=1+x^{2}+x^{4}\) a. Compute \(\langle\mathrm{p}, \mathrm{q}\rangle,\|\mathrm{p}\|, \text { and }\|\mathrm{q}\|\). b. Verify that the identities in Exercises 44 and 45 hold for the vectors \(p \text { and } q\). Equation Transcription: Text Transcription: P4 -2,-1,0,1,2 p=p(x)=x+x3 and q=q(x)=1+x2+x4 ?p,q ?,||p||, and ||q|| p and q
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Table of Contents
Textbook Solutions for Elementary Linear Algebra
Question
a. As shown in Figure \(3.2.6\), the vectors \((k, 0,0),(0, k, 0), \text { and }(0,0, k)\) form the edges of a cube in \(R^{3}\) with diagonal \((k, k, k)\). Similarly, the vectors
\((k, 0,0, \ldots, 0),(0, k, 0, \ldots, 0), \ldots,(0,0,0, \ldots, k)\)
can be regarded as edges of a "cube" in \(R^{n}\) with diagonal \((k, k, k, \ldots, k)\). Show that each of the above edges makes an angle of \(\theta\) with the diagonal, where \(\cos \theta=1 / \sqrt{n}\).
b. (Calculus required) What happens to the angle \(\theta\) in part \((a)\) as the dimension of \(R^{n}\) approaches \(\infty\) ?
Solution
The first step in solving 6 problem number trying to solve the problem we have to refer to the textbook question: a. As shown in Figure \(3.2.6\), the vectors \((k, 0,0),(0, k, 0), \text { and }(0,0, k)\) form the edges of a cube in \(R^{3}\) with diagonal \((k, k, k)\). Similarly, the vectors\((k, 0,0, \ldots, 0),(0, k, 0, \ldots, 0), \ldots,(0,0,0, \ldots, k)\)can be regarded as edges of a "cube" in \(R^{n}\) with diagonal \((k, k, k, \ldots, k)\). Show that each of the above edges makes an angle of \(\theta\) with the diagonal, where \(\cos \theta=1 / \sqrt{n}\).b. (Calculus required) What happens to the angle \(\theta\) in part \((a)\) as the dimension of \(R^{n}\) approaches \(\infty\) ?
From the textbook chapter Inner Product Spaces you will find a few key concepts needed to solve this.
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