Solved: A uniform aluminum beam 9.00 m long, weighing 300

Chapter 11, Problem 11.12

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QUESTION:

A uniform aluminum beam 9.00 m long, weighing 300 N, rests symmetrically on two supports 5.00 m apart (Fig. E11.12). A boy weighing 600 N starts at point A and walks toward the right.

(a) In the same diagram construct two graphs showing the upward forces \(F_{A} \text { and } F_{B}\) exerted on the beam at points A and B, as functions of the coordinate x of the boy. Let 1 cm = 100 N vertically, and 1 cm = 1.00 m horizontally.

(b) From your diagram, how far beyond point B can the boy walk before the beam tips?

(c) How far from the right end of the beam should support B be placed so that the boy can walk just to the end of the beam without causing it to tip?

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QUESTION:

A uniform aluminum beam 9.00 m long, weighing 300 N, rests symmetrically on two supports 5.00 m apart (Fig. E11.12). A boy weighing 600 N starts at point A and walks toward the right.

(a) In the same diagram construct two graphs showing the upward forces \(F_{A} \text { and } F_{B}\) exerted on the beam at points A and B, as functions of the coordinate x of the boy. Let 1 cm = 100 N vertically, and 1 cm = 1.00 m horizontally.

(b) From your diagram, how far beyond point B can the boy walk before the beam tips?

(c) How far from the right end of the beam should support B be placed so that the boy can walk just to the end of the beam without causing it to tip?

ANSWER:

Step 1 of 8

We have,

The length of the beam, L = 9 m

The weight of the bar, \(W_{\mathrm{bar}}=300\mathrm{\ N}\)

The weight of the boy, W = 600 N

The beam rests on two supports 5 m apart.

The boy starts at point A and walks toward the right.

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