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The four bonds of carbon tetrachloride (CCl4) are polar,
Chapter 10, Problem 67P(choose chapter or problem)
The four bonds of carbon tetrachloride (\(CCl_4\)) are polar, but the molecule is nonpolar because the bond polarity is canceled by the symmetric tetrahedral shape. When other atoms substitute for some of the \(Cl\) atoms, the symmetry is broken and the molecule becomes polar. Use Figure 9.19 (p. 297) to rank the following molecules from the least polar to the most polar: \(CH_2Br_2, CF_2Cl_2, CH_2F_2, CH_2C1_2, CBr_4, CF_2Br_2\).
FIGURE 9.19 The Pauling electronegativity (EN) scale. The EN is shown by the height of the post with the value on top. The key indicates arbitrary EN cutoffs. In the main groups, EN generally increases from left to right and decreases from top to bottom. The noble gases are not shown. The transition and inner transition elements show relatively little change in EN. Hydrogen is shown near elements of similar EN.
Questions & Answers
QUESTION:
The four bonds of carbon tetrachloride (\(CCl_4\)) are polar, but the molecule is nonpolar because the bond polarity is canceled by the symmetric tetrahedral shape. When other atoms substitute for some of the \(Cl\) atoms, the symmetry is broken and the molecule becomes polar. Use Figure 9.19 (p. 297) to rank the following molecules from the least polar to the most polar: \(CH_2Br_2, CF_2Cl_2, CH_2F_2, CH_2C1_2, CBr_4, CF_2Br_2\).
FIGURE 9.19 The Pauling electronegativity (EN) scale. The EN is shown by the height of the post with the value on top. The key indicates arbitrary EN cutoffs. In the main groups, EN generally increases from left to right and decreases from top to bottom. The noble gases are not shown. The transition and inner transition elements show relatively little change in EN. Hydrogen is shown near elements of similar EN.
ANSWER:Step 1 of 3
When it comes to the polarity of molecules, both the geometry and the electronegativity differences between atoms are key factors. Let's examine six molecules: Dibromomethane \(\left(\mathrm{CH}_{2} \mathrm{Br}_{2}\right)\), Dichlorodifluoromethane \(\left(\mathrm{CF}_{2} \mathrm{Cl}_{2}\right)\), Difluoromethane (CH?F?), Dichloromethane \(\left(\mathrm{CH}_{2} \mathrm{Cl}_{2}\right)\), Tetrabromomethane \(\left(\mathrm{CBr}_{4}\right)\), and Difluorodibromomethane \(\left(\mathrm{CF}_{2} \mathrm{Br}_{2}\right)\) to rank them from least polar to most polar.