Solution Found!
Solved: From the following heats of combustion, calculate
Chapter 6, Problem 63P(choose chapter or problem)
From the following heats of combustion,
\(\mathrm{CH}_{3} \mathrm{OH}(l)+\frac{3}{2} \mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)\)
\(\Delta H_{r x n}^{\circ}=-726.4\ \mathrm{kJ} / \mathrm{mol}\)
\(C(\text { graphite })+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(\mathrm{g})\)
\(\Delta H_{r x n}^{\circ}=-393.5\ \mathrm{kJ} / \mathrm{mol}\)
\(\mathrm{H}_{2}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\)
\(\Delta H_{r x n}^{\circ}=-285.8\ \mathrm{kJ} / \mathrm{mol}\)
calculate the enthalpy of formation of methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) from its elements:
\(\mathrm{C}(\text { graphite })+2 \mathrm{H}_{2}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \rightarrow \mathrm{CH}_{3} \mathrm{OH}(\mathrm{l})\)
Questions & Answers
QUESTION:
From the following heats of combustion,
\(\mathrm{CH}_{3} \mathrm{OH}(l)+\frac{3}{2} \mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)\)
\(\Delta H_{r x n}^{\circ}=-726.4\ \mathrm{kJ} / \mathrm{mol}\)
\(C(\text { graphite })+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(\mathrm{g})\)
\(\Delta H_{r x n}^{\circ}=-393.5\ \mathrm{kJ} / \mathrm{mol}\)
\(\mathrm{H}_{2}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\)
\(\Delta H_{r x n}^{\circ}=-285.8\ \mathrm{kJ} / \mathrm{mol}\)
calculate the enthalpy of formation of methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) from its elements:
\(\mathrm{C}(\text { graphite })+2 \mathrm{H}_{2}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \rightarrow \mathrm{CH}_{3} \mathrm{OH}(\mathrm{l})\)
ANSWER:Step 1 of 3
Here, we are going to determine the enthalpy of formation of methanol from its elements.
Given that,
---(1)
-----(2)
------(3)