Step by step solution Step 1 of 3 Determine the symmetry of function E E, °f E is even function. Step 2 of 3 Suppose that function g (x) is E(x)°E(x). Let’s find the value of g (-x): g(x)=E(x) E(°) Since E(x) E°x) is E(E(x))than g(x) = E(E(x)) g(-x)=E(E(x))......(1) E(x) is even, therefore E(-x)=E(x) . Based on this, relation (1) becomes: g(-x)=E(E(x)) g(-x)=E(E(x)) It is obvious that g(x) = g(x). Thus the function E(x) E(°) is even and has symmetry about y-axis. Also we can say that the inner and outer functions are same and it is even, so their ranges contain positive real numbers.
Textbook: Calculus: Early Transcendentals
Author: William L. Briggs, Lyle Cochran, Bernard Gillett
The answer to “69AE” is broken down into a number of easy to follow steps, and 1 words. Since the solution to 69E from 1.1 chapter was answered, more than 337 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Calculus: Early Transcendentals, edition: 1. The full step-by-step solution to problem: 69E from chapter: 1.1 was answered by , our top Calculus solution expert on 03/03/17, 03:45PM. Calculus: Early Transcendentals was written by and is associated to the ISBN: 9780321570567. This full solution covers the following key subjects: . This expansive textbook survival guide covers 85 chapters, and 5218 solutions.