?(a) The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation \(F=\kappa\left(Q_{1} Q_{2} / d

Chapter 5, Problem 5.15

(choose chapter or problem)

(a) The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation \(F=\kappa\left(Q_{1} Q_{2} / d^{2}\right)\) where \(\kappa=8.99 \times 10^{9} \mathrm{~N}-\mathrm{m}^{2} / \mathrm{C}^{2}\), \(Q_{1}\) and \(Q_{2}\) are the charges of the two objects in Coulombs, and d is the distance separating the two objects in meters. What is the electrostatic force of attraction (in Newtons) between an electron and a proton that are separated by \(1.00 \times 10^{2} \mathrm{pm}\)?

(b) The force of gravity acting between two objects is given by the equation \(F=G\left(m_{1} m_{2} / d^{2}\right)\), where G is the gravitational constant, \(G=6.674 \times 10^{-11} \mathrm{~N}-\mathrm{m}^{2} / \mathrm{kg}^{2}\), \(m_{1} \text { and } m_{2}\) are the masses of the two objects, and d is the distance separating them. What is the gravitational force of attraction (in Newtons) between the electron and proton?

(c) How many times larger is the electrostatic force of attraction?

Text Transcription:

F = \kappa(Q_1Q_2/d^2)

\kappa = 8.99 X 109 N-m^2/C^2

Q_1

Q_2

1.00 X 10^2 pm

 F = G(m_1m_2/d^2)

G = 6.674 X 10^-11N-m^2/kg^2

m_1 and m_2