For the following exercises, sketch and describe the cylindrical surface of the given equation. \(\text { [T] } x^{2}+z^{2}=1\) Text Transcription: text [T] x^2+z^2=1
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Table of Contents
Textbook Solutions for Calculus Volume 3
Question
For the following exercises, match the given quadric surface with its corresponding equation in standard form.
a. \(\frac{x^{2}}{4}+\frac{y^{2}}{9}-\frac{z^{2}}{12}=1\)
b. \(\frac{x^{2}}{4}-\frac{y^{2}}{9}-\frac{z^{2}}{12}=1\)
c. \(\frac{x^{2}}{4}+\frac{y^{2}}{9}+\frac{z^{2}}{12}=1\)
d. \(z^{2}=4 x^{2}+3 y^{2}\)
e. \(z=4 x^{2}-y^{2}\)
f. \(4 x^{2}+y^{2}-z^{2}=0\)
Hyperboloid of two sheets
Text Transcription:
frac x^2/4+frac y^2/9}-fracz^2/12=1
frac x^2/4-frac y^2/9-fracz^2/12=1
frac x^2/4+frac y^2/9+fracz^2/12=1
z^2=4 x^2+3 y^2
z=4 x^2-y^2
4 x^2+y^2-z^2=0
Solution
The first step in solving 2.6 problem number trying to solve the problem we have to refer to the textbook question: For the following exercises, match the given quadric surface with its corresponding equation in standard form.a. \(\frac{x^{2}}{4}+\frac{y^{2}}{9}-\frac{z^{2}}{12}=1\)b. \(\frac{x^{2}}{4}-\frac{y^{2}}{9}-\frac{z^{2}}{12}=1\)c. \(\frac{x^{2}}{4}+\frac{y^{2}}{9}+\frac{z^{2}}{12}=1\)d. \(z^{2}=4 x^{2}+3 y^{2}\)e. \(z=4 x^{2}-y^{2}\)f. \(4 x^{2}+y^{2}-z^{2}=0\)Hyperboloid of two sheetsText Transcription:frac x^2/4+frac y^2/9}-fracz^2/12=1frac x^2/4-frac y^2/9-fracz^2/12=1frac x^2/4+frac y^2/9+fracz^2/12=1z^2=4 x^2+3 y^2z=4 x^2-y^24 x^2+y^2-z^2=0
From the textbook chapter Quadric Surfaces you will find a few key concepts needed to solve this.
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full solution