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Electric generating plants transport large amounts of hot
Chapter 6, Problem 6.109(choose chapter or problem)
Electric generating plants transport large amounts of hot water through metal pipes, and oxygen dissolved in the water can cause a major corrosion problem. Hydrazine (N2H4) added to the water avoids the problem by reacting with the oxygen: About 4 10 7 kg of hydrazine is produced every year by reacting ammonia with sodium hypochlorite in the Raschig process: 2NH3(aq) NaOCl(aq) N2H4(aq) NaCl(aq) H2O(l) H rxn ? ?151 kJ (a) If H f of NaOCl(aq) ? ? 346 kJ/mol, find H f of N2H4(aq). (b) What is the heat released when aqueous N2H4 is added to 5.00 10 3 L of plant water that is 2.50 10 4 M O2?
Questions & Answers
QUESTION:
Electric generating plants transport large amounts of hot water through metal pipes, and oxygen dissolved in the water can cause a major corrosion problem. Hydrazine (N2H4) added to the water avoids the problem by reacting with the oxygen: About 4 10 7 kg of hydrazine is produced every year by reacting ammonia with sodium hypochlorite in the Raschig process: 2NH3(aq) NaOCl(aq) N2H4(aq) NaCl(aq) H2O(l) H rxn ? ?151 kJ (a) If H f of NaOCl(aq) ? ? 346 kJ/mol, find H f of N2H4(aq). (b) What is the heat released when aqueous N2H4 is added to 5.00 10 3 L of plant water that is 2.50 10 4 M O2?
ANSWER:Problem 6.109
Electric generating plants transport large amounts of hot water through metal pipes, and oxygen dissolved in the water can cause a major corrosion problem. Hydrazine added to the water avoids the problem by reacting with the oxygen:
About 4 x 10 7 kg of hydrazine is produced every year by reacting ammonia with sodium hypochlorite in the Raschig process:
(a) If of NaOCl(aq) = -346 kJ/mol, find of
(b) What is the heat released when aqueous is added to 5.00 x 103 L of plant water that is 2.50 x 104 M ?
Step by step solution
Step 1 of 2
(a)
The thermochemical equation is as follows:
.......(1)
Use the following equation to determine the standard heat of formation for from equation ( 1 ).
Here represents the sum of terms, m and n are the number of moles of products and reactants, respectively. The term is the standard heat of formation.
=34 kJ/mol
Thus, the standard heat of formation for will be 34 kJ / mol.
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