×
Log in to StudySoup
Get Full Access to University Physics, Volume 3 - 17 Edition - Chapter 4 - Problem 76
Join StudySoup for FREE
Get Full Access to University Physics, Volume 3 - 17 Edition - Chapter 4 - Problem 76

Already have an account? Login here
×
Reset your password

University Physics, Volume 3 | 17th Edition | ISBN: 9781938168185 | Authors: Samuel J. Ling ISBN: 9781938168185 2032

Solution for problem 76 Chapter 4

University Physics, Volume 3 | 17th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
University Physics, Volume 3 | 17th Edition | ISBN: 9781938168185 | Authors: Samuel J. Ling

University Physics, Volume 3 | 17th Edition

4 5 1 384 Reviews
10
2
Problem 76

X-Ray Diffraction

On a certain crystal, a first-order X-ray diffraction maximum is observed at an angle of \(27.1^{\circ}\) relative to its surface, using an X-ray source of unknown wavelength. Additionally, when illuminated with a different, this time of known wavelength 0.137 nm, a second-order maximum is detected at \(37.3^{\circ}\). Determine (a) the spacing between the reflecting planes, and (b) the unknown wavelength.

Text Transcription:

27.1 degrees

37.3 degrees

Step-by-Step Solution:
Step 1 of 3

Energy Stored in Capacitors U = 1 qV 2 q = CV 1 2 U = CV or 2 1 q2 U = 2 C 37 Energy Density in Capacitors (1)  We define the , u, as the electric potential energy per unit volume  Taking the ideal case of a parallel plate capacitor that has no fringe field, the volume between the plates is the area of each plate times the distance between the plates, Ad  Inserting our formula for the capacitance of a parallel plate capacitor we find 38 Energy Density in Capacitors (2)  Recognizing that V/d is the magnitude of the electric field, E, we obtain an expression for the electric potential energy density for parallel plate capacitor  This result, which we derived for the parallel plate capacitor, is in fact completely general.  This equation holds for all electric fields produced in any way •The formula gives the quantity of electric field energy per unit volume. 39 Example: Isolated Conducting Sphere (1)  An isolated conducting sphere whose radius R is 6.85 cm has a charge of q=1.25 nC. Question 1: How much potential energy is stored in the electric field of the charged conductor Answer: Key Idea: An isolated sphere has a capacitance ofC=4πε R (see prev

Step 2 of 3

Chapter 4, Problem 76 is Solved
Step 3 of 3

Textbook: University Physics, Volume 3
Edition: 17
Author: Samuel J. Ling
ISBN: 9781938168185

This full solution covers the following key subjects: . This expansive textbook survival guide covers 11 chapters, and 1200 solutions. University Physics, Volume 3 was written by Aimee Notetaker and is associated to the ISBN: 9781938168185. This textbook survival guide was created for the textbook: University Physics, Volume 3 , edition: 17. The full step-by-step solution to problem: 76 from chapter: 4 was answered by Aimee Notetaker, our top Physics solution expert on 03/18/22, 10:28AM. The answer to “?X-Ray DiffractionOn a certain crystal, a first-order X-ray diffraction maximum is observed at an angle of \(27.1^{\circ}\) relative to its surface, using an X-ray source of unknown wavelength. Additionally, when illuminated with a different, this time of known wavelength 0.137 nm, a second-order maximum is detected at \(37.3^{\circ}\). Determine (a) the spacing between the reflecting planes, and (b) the unknown wavelength.Text Transcription:27.1 degrees37.3 degrees” is broken down into a number of easy to follow steps, and 64 words. Since the solution to 76 from 4 chapter was answered, more than 202 students have viewed the full step-by-step answer.

Other solutions

People also purchased

Related chapters

Unlock Textbook Solution

Enter your email below to unlock your verified solution to: