?The value of \(K_{a}\) for nitrous acid \(\left(\mathrm{HNO}_{2}\right)\) at

Chapter 19, Problem 19.83

(choose chapter or problem)

The value of \(K_{a}\) for nitrous acid \(\left(\mathrm{HNO}_{2}\right)\) at \(25^{\circ} \mathrm{C}\) is given in Appendix D.

(a) Write the chemical equation for the equilibrium that corresponds to \(K_{a}\).

(b) By using the value of \(K_{a}\), calculate \(\Delta G^{\circ}\) for the dissociation of nitrous acid in aqueous solution.

(c) What is the value of \(\Delta G\) at equilibrium?

(d) What is the value of \(\Delta G\) when \(\left[\mathrm{H}^{+}\right]=5.0 \times 10^{-2} \mathrm{M}\), \(\left[\mathrm{NO}_{2}^{-}\right]=6.0 \times 10^{-4} \mathrm{M}\), and \(\left[\mathrm{HNO}_{2}\right]=0.20 \mathrm{M}\) ?

Text Transcription:

Ka

(HNO2)

25^circ C

Delta G^circ

Delta G

[H+] = 5.0 x 10-2 M

[NO2 -] = 6.0 x 10-4 M

[HNO2] = 0.20 M