How do two structural isomers differ from each other?
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Textbook Solutions for Conceptual Physical Science
Question
A property of polymers is their glass transition temperature, \(T_{g}\), which is the approximate temperature below which the polymer is hard and rigid, but above which the polymer is soft and flexible. The \(T_{g}\) of polyethylene is a chilly -125\({ }^{\circ} \mathrm{C}\), which is why polyethylene food wrap is flexible at ambient temperatures. Consider the two polymers polyethylene terephthalate (PETE) and polystyrene (PS). Which do you suppose has the higher \(T_{g}\)? Dip some plastics of these two polymers in boiling water to find out. A common polymer used to make chewing gum is polyvinyl acetate, with a Tg of about 28\({ }^{\circ} \mathrm{C}\), which is below body temperature but above room temperature. That’s why most chewing gums are hard until they soften up in your warm mouth. Drink ice water while chewing gum and note how it quickly hardens.
Text Transcription:
T_g
^circC
Solution
The first step in solving 19 problem number trying to solve the problem we have to refer to the textbook question: A property of polymers is their glass transition temperature, \(T_{g}\), which is the approximate temperature below which the polymer is hard and rigid, but above which the polymer is soft and flexible. The \(T_{g}\) of polyethylene is a chilly -125\({ }^{\circ} \mathrm{C}\), which is why polyethylene food wrap is flexible at ambient temperatures. Consider the two polymers polyethylene terephthalate (PETE) and polystyrene (PS). Which do you suppose has the higher \(T_{g}\)? Dip some plastics of these two polymers in boiling water to find out. A common polymer used to make chewing gum is polyvinyl acetate, with a Tg of about 28\({ }^{\circ} \mathrm{C}\), which is below body temperature but above room temperature. That’s why most chewing gums are hard until they soften up in your warm mouth. Drink ice water while chewing gum and note how it quickly hardens.Text Transcription:T_g^circC
From the textbook chapter Organic Compounds you will find a few key concepts needed to solve this.
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