A ball on the end of a string is whirled around in a horizontal circle of radius 0.300 m. The plane of the circle is 1.20 m above the ground. The string breaks and the ball lands 2.00 m (horizontally) away from the point on the ground directly beneath the ball’s location when the string breaks. Find the radial acceleration of the ball during its circular motion.
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Textbook Solutions for Physics for Scientists and Engineer with Modern Physics
Question
In the What If? section of Example 4.5, it was claimed that the maximum range of a ski jumper occurs for a launch angle \(\theta\) given by
\(\theta\) = \(45^{\circ}\) - \(\frac{\phi}{2}\)
where \(\phi\) is the angle the hill makes with the horizontal in Figure 4.15. Prove this claim by deriving the equation above.
Solution
The first step in solving 4 problem number trying to solve the problem we have to refer to the textbook question: In the What If? section of Example 4.5, it was claimed that the maximum range of a ski jumper occurs for a launch angle \(\theta\) given by\(\theta\) = \(45^{\circ}\) - \(\frac{\phi}{2}\)where \(\phi\) is the angle the hill makes with the horizontal in Figure 4.15. Prove this claim by deriving the equation above.
From the textbook chapter Motion in Two Dimensions you will find a few key concepts needed to solve this.
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