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Get Full Access to Probability And Statistics For Engineers And The Scientists - 9 Edition - Chapter 3 - Problem 69e
Get Full Access to Probability And Statistics For Engineers And The Scientists - 9 Edition - Chapter 3 - Problem 69e

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# Each of 12 refrigerators of a certain type has been

ISBN: 9780321629111 32

## Solution for problem 69E Chapter 3

Probability and Statistics for Engineers and the Scientists | 9th Edition

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Problem 69E

Each of 12 refrigerators of a certain type has been returned to a distributor because of an audible, high-pitched, oscillating noise when the refrigerators are running. Suppose that 7 of these refrigerators have a defective compressor and the other 5 have less serious problems. If the refrigerators are examined in random order, let X be the number among the first 6 examined that have a defective compressor. a. Calculate P(X = 4) and P(X ? 4) b. Determine the probability that X exceeds its mean value by more than 1 standard deviation. c. Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly selected refrigerators that have defective compressors, describe a less tedious way to calculate (at least approximately) P(X ?5) than to use the hypergeometric pmf.

Step-by-Step Solution:

Answer: Step 1 of 3 Suppose that 7 of these refrigerators have a defective compressor and the other 5 have less serious problems. If the refrigerators are examined in random order, let X be the number among the first 6 examined that have a defective compressor. Taking everything mentioned above into consideration we can see that this is a hypergeometric distribution, where h(x;n, M,N) = h(x;6, 7, 12). a. Calculate P(X = 4) and P(X 4) Compute P(X = 4), P(X 4) The Hypergeometric distribution formula is as shown below i) We have, MC x (N M)C (n x) P(X = x) = NC n 7C 4 (12 7)C(6 4) P(X = 4) = 12C 6 P(X = 4) = 924 = 0.3787 Therefore, P(X = 4) = 0.3787 ii) Now, P(X 4) = 1 P(X > 4) P(X 4) = 1 (P(X = 5) + P(X = 6)) 7C5 (12 7(6 5)7C 6 (12 7(6 6) = 1 ( 12C 6 + 12C6 ) 105 7 = 1 ( 924 + 924 ) = 1 - 0.1212 = 0.8788 Hence,P(X 4) = 0.8788.

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321629111

Probability and Statistics for Engineers and the Scientists was written by and is associated to the ISBN: 9780321629111. The full step-by-step solution to problem: 69E from chapter: 3 was answered by , our top Statistics solution expert on 05/06/17, 06:21PM. This full solution covers the following key subjects: Refrigerators, defective, calculate, examined, less. This expansive textbook survival guide covers 18 chapters, and 1582 solutions. The answer to “Each of 12 refrigerators of a certain type has been returned to a distributor because of an audible, high-pitched, oscillating noise when the refrigerators are running. Suppose that 7 of these refrigerators have a defective compressor and the other 5 have less serious problems. If the refrigerators are examined in random order, let X be the number among the first 6 examined that have a defective compressor. a. Calculate P(X = 4) and P(X ? 4) b. Determine the probability that X exceeds its mean value by more than 1 standard deviation. c. Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly selected refrigerators that have defective compressors, describe a less tedious way to calculate (at least approximately) P(X ?5) than to use the hypergeometric pmf.” is broken down into a number of easy to follow steps, and 138 words. This textbook survival guide was created for the textbook: Probability and Statistics for Engineers and the Scientists, edition: 9. Since the solution to 69E from 3 chapter was answered, more than 861 students have viewed the full step-by-step answer.

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