A lead fishing weight with a mass of 57 g absorbs 146 cal of heat. If its initial temperature is 47 °C, what is its final temperature?

Solution 84P

We have 57g of lead, which absorbs 146 cal of heat. The heat capacity of lead is = 0.128 j/g oC or 0.054 cal/g oC.

It is known that,

dH = m C dT

Where dH is the change in heat absorbed.

m is the mass of the sample (lead)

C is the specific heat capacity in j/g oC

dT(T2-T1) is the change in temperature(Celsius)

146 cal = (57 grams) (0.054 cal/gram OC) (T2 - 47)

146 = 3.078 (T2 -...