A lead fishing weight with a mass of 57 g absorbs 146 cal of heat. If its initial temperature is 47 °C, what is its final temperature?
We have 57g of lead, which absorbs 146 cal of heat. The heat capacity of lead is = 0.128 j/g oC or 0.054 cal/g oC.
It is known that,
dH = m C dT
Where dH is the change in heat absorbed.
m is the mass of the sample (lead)
C is the specific heat capacity in j/g oC
dT(T2-T1) is the change in temperature(Celsius)
146 cal = (57 grams) (0.054 cal/gram OC) (T2 - 47)
146 = 3.078 (T2 -...