How many hydrogen atoms are in each of the formulas in Question 35?
Solution 36P
Here, we are going to calculate the number of Hydrogen atoms (H) present in each molecular compound.
Atom is the smallest tiny representation of an atom.
Chemical formula is the representation of the number of atoms present in the molecule or molecular compound .
(a) H3PO4
3 H + P + 4O -----> H3PO4
Here, molecular compound H3PO4 (phosphoric acid) is composed of three hydrogen atoms (H) , one phosphorus atom (P) and four oxygen atoms (O).
Thus, the molecular compound H3PO4 (phosphoric acid) has three(3) hydrogen atoms (H).
(b) Na2HPO4
2Na + H +P + 4O -----> Na2HPO4
Here, molecular compound Na2HPO4 (sodium phosphate) is composed of two sodium atoms (Na), one hydrogen atoms (H) , one phosphorus atom (P) and four oxygen atoms (O).
Thus, the molecular compound Na2HPO4 (sodium phosphate) has one (1) hydrogen (H) atom.
(c) Ca(HCO3)2
Ca + 2H +2C + 6O -----> Ca(HCO3)2
Here, molecular compound Ca(HCO3)2 (calcium bicarbonate) is composed of one calcium atom (Ca), two hydrogen atoms (H) , two carbon atoms (C) and six oxygen atoms (O).
Thus, the molecular compound Ca(HCO3)2 (calcium bicarbonate) has two (2) Hydrogen (H) atoms.
(d) Ba(C2H3O2)2
Ba + 6H +4C + 4O -----> Ba(C2H3O2)2
Here, molecular compound Ba(C2H3O2)2(barium acetate) is composed of one Barium atom (Ba), six hydrogen atoms (H) , four carbon atoms (C) and four oxygen atoms (O).
Thus, the molecular compound Ba(C2H3O2)2(barium acetate) has six(6) Hydrogen atoms (H).