Which is a stronger base?
a. \(H S^{-} \text {or } H O^{-}\) c. \(\mathrm{CH}_{3} \mathrm{OH} \text { or } \mathrm{CH}_{3} \mathrm{O}^{-}\) e. \(\mathrm{CH}_{3} \mathrm{COO}^{-} \text {or } \mathrm{CF}_{3} \mathrm{COO}^{-}\)
b. \(\mathrm{CH}_{3} \mathrm{O}^{-} \text {or } \mathrm{CH}_{3} \overline{\mathrm{N}} H\) d. \(\mathrm{Cl}^{-} \text {or } \mathrm{Br}^{-}\) f. \(\mathrm{CH}_{3} \mathrm{CHClCOO}^{-} \text {or } \mathrm{CH}_{3} \mathrm{CHBrCOO}^{-}\)
Equation Transcription:
Text Transcription:
HS^- or HO^-
CH_3 O^- or CH_3 overline N H
CH_3 OH or CH_3 O^-
Cl^- or Br^-
CH_3 COO^- or CF_3 COO^-
CH_3 CHClCOO^- or CH_3 CHBrCOO^-
Step 1 of 6
Here we have to find out which is stronger base among the given molecules.
It is known that the relative acidity depends on the following two factors:
1. Atomic size
2. A Stronger base has weaker conjugate acid.
a.
Here the bases are formed from its conjugate acid
and
. Here
is the stronger acid than that of
due to the presence of S-atom, which has big atomic size than O-atom.
The conjugate base of the strong acid is less basic, thus is the stronger base than
.
__________________________