Solution Found!
For each redox reaction, identify the substance being oxidized, the substance being
Chapter 16, Problem 43P(choose chapter or problem)
For each redox reaction, identify the substance being oxidized, the substance being reduced, the oxidizing agent, and the reducing agent.
(a) \(\mathrm{N}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2~ \mathrm{NO}(g)\)
(b) \(2~ \mathrm{CO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2~ \mathrm{CO}_{2}(g)\)
(c) \(\mathrm{SbCl}_{3}(g)+\mathrm{Cl}_{2}(g) \longrightarrow \mathrm{SbCl}_{5}(g)\)
Equation Transcription:
Text Transcription:
N_2(g)+O_2(g) rightarrow 2 NO(g)
2 CO(g)+O_2(g) rightarrow 2 CO_2(g)
SbCl_3(g)+Cl_2(g) rightarrow SbCl_5(g)
Questions & Answers
QUESTION:
For each redox reaction, identify the substance being oxidized, the substance being reduced, the oxidizing agent, and the reducing agent.
(a) \(\mathrm{N}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2~ \mathrm{NO}(g)\)
(b) \(2~ \mathrm{CO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2~ \mathrm{CO}_{2}(g)\)
(c) \(\mathrm{SbCl}_{3}(g)+\mathrm{Cl}_{2}(g) \longrightarrow \mathrm{SbCl}_{5}(g)\)
Equation Transcription:
Text Transcription:
N_2(g)+O_2(g) rightarrow 2 NO(g)
2 CO(g)+O_2(g) rightarrow 2 CO_2(g)
SbCl_3(g)+Cl_2(g) rightarrow SbCl_5(g)
ANSWER:
Solution 43P :
Step 1:
An oxidizing agent is a chemical specie that removes one or more oxygen atom of other chemical substances in the redox chemical reaction and thus it gains electrons in a chemical reaction.
A reducing agent is a chemical specie that donates electrons to another chemical substance in a redox chemical reaction and thus it loses electrons in a chemical reaction.