Solution Found!
For each pair, predict the stronger nucleophile in the
Chapter 8, Problem 16P(choose chapter or problem)
For each pair, predict the stronger nucleophile in the \(\mathrm{S}_{\mathrm{N}} 2\) reaction (using an alcohol as the solvent). Explain your prediction.
(a) \(left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{3} \mathrm{~N} \text { or }\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{2} \mathrm{NH}\)
(b) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{O} \text { or }\left(\mathrm{CH}_{3}\right)_{2} \mathrm{~S}\)
(c) \(\mathrm{NH}_{3} \text { or } \mathrm{PH}_{3}\)
(d) \(\mathrm{CH}_{3} \mathrm{~S}^{-} \text {or } \mathrm{H}_{2} \mathrm{~S}\)
(e) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N or}\left(\mathrm{CH}_{3}\right)_{2} \mathrm{O}\)
(f) \(\mathrm{CH}_{3} \mathrm{COO}^{-} \text {or } \mathrm{CF}_{3} \mathrm{COO}^{-}\)
(g) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHO}^{-} \text {or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{O}^{-}\)
(h) \(\mathrm{I}^{-} \text {or } \mathrm{Cl}^{-}\)
Problem-solving Hint
Steric hindrance (bulkiness) hinders nucleophilicity \(\left(\mathrm{S}_{\mathrm{N}} 2\right)\) more than it hinders basicity.
Equation Transcription:
Text Transcription:
S_N2
(CH_3CH_2)_3 N or (CH_3CH_2)_2NH
(CH_3)_2O or (CH_3)_2S
NH_3 or PH_3
CH_3S- or H_2S
(CH_3)_3N or (CH_3)_2O
CH_3COO- or CF_3COO-
(CH_3)_2CHO- or CH_3CH_2CH_2O-
I- or Cl-
(S_N2)
Questions & Answers
QUESTION:
For each pair, predict the stronger nucleophile in the \(\mathrm{S}_{\mathrm{N}} 2\) reaction (using an alcohol as the solvent). Explain your prediction.
(a) \(left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{3} \mathrm{~N} \text { or }\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{2} \mathrm{NH}\)
(b) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{O} \text { or }\left(\mathrm{CH}_{3}\right)_{2} \mathrm{~S}\)
(c) \(\mathrm{NH}_{3} \text { or } \mathrm{PH}_{3}\)
(d) \(\mathrm{CH}_{3} \mathrm{~S}^{-} \text {or } \mathrm{H}_{2} \mathrm{~S}\)
(e) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N or}\left(\mathrm{CH}_{3}\right)_{2} \mathrm{O}\)
(f) \(\mathrm{CH}_{3} \mathrm{COO}^{-} \text {or } \mathrm{CF}_{3} \mathrm{COO}^{-}\)
(g) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHO}^{-} \text {or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{O}^{-}\)
(h) \(\mathrm{I}^{-} \text {or } \mathrm{Cl}^{-}\)
Problem-solving Hint
Steric hindrance (bulkiness) hinders nucleophilicity \(\left(\mathrm{S}_{\mathrm{N}} 2\right)\) more than it hinders basicity.
Equation Transcription:
Text Transcription:
S_N2
(CH_3CH_2)_3 N or (CH_3CH_2)_2NH
(CH_3)_2O or (CH_3)_2S
NH_3 or PH_3
CH_3S- or H_2S
(CH_3)_3N or (CH_3)_2O
CH_3COO- or CF_3COO-
(CH_3)_2CHO- or CH_3CH_2CH_2O-
I- or Cl-
(S_N2)
ANSWER:
Solution 16P
Step 1
The reaction relies on the rear-side attack of a strong nucleophile on a sterically unhindered electrophile containing a good leaving group.
(a)
The pair of compounds are and.
Note that is a secondary amine, and is less hindered than the other compound (which is a tertiary amine). There is less steric hindrance around the secondary amine, and so it will be the stronger nucleophile; it can more easily attack the electrophile.
Therefore, will be the stronger nucleophile.