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# Calculate the mass in grams of each elemental sample.(a) ISBN: 9780321910295 34

## Solution for problem 38P Chapter 6

Introductory Chemistry | 5th Edition

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Problem 38P

Calculate the mass in grams of each elemental sample.

(a) 1.32 × 1020uranium atoms

(b) 2.55 × 1022zinc atoms

(d) 6.59 × 1024silicon atoms

Step-by-Step Solution:

Solution 38P

Here, we are going to calculate the mass in grams of each of the given elemental sample.

Step 1:

One mole of any species is that quantity in number having a mass equal to its atomic or molecular mass in grams.

The number of particles (atoms, molecules or ions) present in 1 mole of any substance is fixed, with a value of 6.022 × 1023. This is an experimentally obtained value. This number is called the Avogadro Constant or Avogadro Number.

Step 2:

Therefore, 1 mole = molar mass

1 mole = Avogadro number of particles

Combining the two statements, we get,

Mass of Avogadro’s number of particles = Molar mass

Therefore, mass of given number of particles = (Molar mass / Avogadro's number) x given number of particles

Thus,

The mass of given elemental sample = (given number of particles/Avogadro's number) x molar mass

Step 3 of 3

##### ISBN: 9780321910295

Since the solution to 38P from 6 chapter was answered, more than 1053 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 38P from chapter: 6 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The answer to “Calculate the mass in grams of each elemental sample.(a) 1.32 × 1020uranium atoms(b) 2.55 × 1022zinc atoms(c) 4.11 × 1023lead atoms(d) 6.59 × 1024silicon atoms” is broken down into a number of easy to follow steps, and 25 words. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. This full solution covers the following key subjects: atoms, mass, elemental, grams, lead. This expansive textbook survival guide covers 19 chapters, and 2045 solutions.

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