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A sugar crystal contains approximately 1.8 × 1017 sucrose (C12H22O11) molecules. What is

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 55P Chapter 6

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 55P

A sugar crystal contains approximately 1.8 × 1017 sucrose (C12H22O11) molecules. What is its mass in milligrams?

Step-by-Step Solution:

Solution 55P

Here, we are going to calculate the mass of sugar crystal containing approximately 1.8 x 1017 sucrose molecules.

Step 1:

One mole of any species is that quantity in number having a mass equal to its atomic or molecular mass in grams.

The number of particles (atoms, molecules or ions) present in 1 mole of any substance is fixed, with a value of 6.022 × 1023. This is an experimentally obtained value. This number is called the Avogadro Constant or Avogadro Number.

Step2:

Therefore, 1 mole = molar mass

            1 mole = Avogadro number of particles

Combining the two statements, we get,

        Mass of Avogadro’s number of particles = Molar mass

Therefore, mass of given number of particles = (Molar mass / Avogadro's number) x given number of particles

Thus,

The mass of given sucrose sample = (given number of particles/Avogadro's number) x molar mass

Step 3:

Now, molar mass of sucrose(C12H22O11) = (12 x atomic mass of C) + (22 x atomic mass of H) + (11 x atomic mass of O)

                                            = (12 x 12.0107) + (22 x 1.0079) + (11 x 15.9994)

                                            = 144.1284 + 22.1738 + 175.9934

                                            = 342.2956 g/mol

Given number of sucrose molecules = 1.8 x 1017 molecules

Therefore, mass of the sugar crystal = [(1.8 x 1017)/(6.022 × 1023)] x 342.2956 g/mol

                                        = (0.299 x 10-6) x 342.2956 g

                                        = 102.346 x 10-6 g

                                        = 102.346 x 10-6 x 1000 mg        [1 g = 1000 mg]

                                        = 0.102 mg.

Thus, mass of the sugar crystal is 0.102 mg.

                                        

Step 2 of 3

Chapter 6, Problem 55P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

Since the solution to 55P from 6 chapter was answered, more than 1157 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The full step-by-step solution to problem: 55P from chapter: 6 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. The answer to “A sugar crystal contains approximately 1.8 × 1017 sucrose (C12H22O11) molecules. What is its mass in milligrams?” is broken down into a number of easy to follow steps, and 17 words. This full solution covers the following key subjects: approximately, contains, crystal, its, mass. This expansive textbook survival guide covers 19 chapters, and 2046 solutions.

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A sugar crystal contains approximately 1.8 × 1017 sucrose (C12H22O11) molecules. What is