PROBLEM 21P
For each reaction, calculate how many moles of product form when 1.75 mol of the reactant in color completely reacts. Assume there is more than enough of the other reactant.
(a) H2(g) + Cl2(g) → 2HCl(g)
(b) 2 H2(g) + O2(g) → 2 H2O(l)
(c) 2 Na(s) + O2(g) → Na2O2(s)
(d) 2 S(s) + 3 O2(g) →2 SO3(g)
Problem 21P
For each reaction, calculate how many moles of product form when 1.75 mol of the reactant in color completely reacts. Assume there is more than enough of the other reactant.
(a) H2(g) + Cl2(g) ? 2HCl(g)
(b) 2 H2(g) + O2(g) ? 2 H2O(l)
(c) 2 Na(s) + O2(g) ? Na2O2(s)
(d) 2 S(s) + 3 O2(g) ?2 SO3(g)
Step by step solution
Step 1 of 4
(a)
The given chemical reaction is as follows.
From the given reaction,
One mole of hydrogen produces two moles of HCl.
The conversion factor will be ;
Number of moles of hydrogen participated in the reaction = 1.75 mol
Let’s calculate the number of moles of HCl produced by using 1.75 mol of hydrogen.
Therefore, the number of moles of HCl produced from 1.75 moles of 
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