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Solved: For each reaction, calculate how many moles of product form when 1.75 mol of the

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 21P Chapter 8

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 21P

 PROBLEM 21P

For each reaction, calculate how many moles of product form when 1.75 mol of the reactant in color completely reacts. Assume there is more than enough of the other reactant.

(a) H2(g) + Cl2(g) → 2HCl(g)

(b) 2 H2(g) + O2(g) → 2 H2O(l)

(c) 2 Na(s) + O2(g) → Na2O2(s)

(d) 2 S(s) + 3 O2(g) →2 SO3(g)

Step-by-Step Solution:

Problem 21P

For each reaction, calculate how many moles of product form when 1.75 mol of the reactant in color completely reacts. Assume there is more than enough of the other reactant.

(a) H2(g) + Cl2(g) ? 2HCl(g)

(b) 2 H2(g) + O2(g) ? 2 H2O(l)

(c) 2 Na(s) + O2(g) ? Na2O2(s)

(d) 2 S(s) + 3 O2(g) ?2 SO3(g)

                                                            Step by step solution

Step 1 of 4

(a)

The given chemical reaction is as follows.

                                         

From the given reaction,

One mole of hydrogen produces two moles of HCl.

The conversion factor will be ;

Number of moles of hydrogen participated in the reaction = 1.75 mol

Let’s calculate the number of moles of HCl produced by using 1.75 mol of hydrogen.

                 
                                                                 

Therefore, the number of moles of HCl produced from 1.75 moles of  is 3.50 mol HCl.

___________________________________________________________________________

Step 2 of 4

Chapter 8, Problem 21P is Solved
Step 3 of 4

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

The answer to “For each reaction, calculate how many moles of product form when 1.75 mol of the reactant in color completely reacts. Assume there is more than enough of the other reactant.(a) H2(g) + Cl2(g) ? 2HCl(g)(b) 2 H2(g) + O2(g) ? 2 H2O(l)(c) 2 Na(s) + O2(g) ? Na2O2(s)(d) 2 S(s) + 3 O2(g) ?2 SO3(g)” is broken down into a number of easy to follow steps, and 55 words. The full step-by-step solution to problem: 21P from chapter: 8 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Since the solution to 21P from 8 chapter was answered, more than 1563 students have viewed the full step-by-step answer. This full solution covers the following key subjects: reactant, mol, color, completely, enough. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295.

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