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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 8 - Problem 31p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 8 - Problem 31p

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# Answer: For the reaction shown, calculate how many grams of oxygen form when each ISBN: 9780321910295 34

## Solution for problem 31P Chapter 8

Introductory Chemistry | 5th Edition

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Problem 31P

PROBLEM 31P

For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.

2 HgO(s) → 2 Hg(l) + O2(g)

(a) 2.13 g HgO

(b) 6.77 g HgO

(c) 1.55 kg HgO

(d) 3.87 mg HgO

Step-by-Step Solution:
Step 1 of 3

Solution 31P

Here, we are going to calculate the mass of oxygen.

2HgO(s) → 2Hg (l) + O2(g)

(a) 2.13 g HgO

g Hgo = mol Hgo = g O2 = mol O2

Thus,

Molar mass of HgO = 216.59 g/mol

Molar mass of O2 =32 g/mol

2.13 g HgO x x x = 0.157 g

Thus 2.13 g HgO  forms =  0.157 g of O2.

(b) 6.77 g HgO

g Hgo = mol Hgo = g O2 = mol O2

Thus,

Molar mass of HgO = 216.59 g/mol

Molar mass of O2 =32 g/mol

6.77 g HgO x x x = 0.50 g

Thus 6.77 g HgO  forms =  0.50 g of O2.

(c) 1.55 kg HgO

g Hgo = mol Hgo = g O2 = mol O2

Thus,

Molar mass of HgO = 216.59 g/mol

Molar mass of O2 =32 g/mol

1.55 kg HgO x x x x = g =114.50 g

Thus 1.55 kg HgO  forms = 114.50 g of O2 = 0.1145 kg of O2.

(d) 3.87 mg HgO

g HgO = mol HgO = g O2 = mol O2

Thus,

Molar mass of HgO = 216.59 g/mol

Molar mass of O2 =32 g/mol

3.87  mg HgO x x x x = g

=0.2858 x 10-3 g

Thus 3.87 mg HgO  forms = 0.2858 x 10-3 g of O2 = 0.2858 mg of O2.

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

The answer to “For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.2 HgO(s) ? 2 Hg(l) + O2(g)(a) 2.13 g HgO(b) 6.77 g HgO(c) 1.55 kg HgO(d) 3.87 mg HgO” is broken down into a number of easy to follow steps, and 36 words. This full solution covers the following key subjects: hgo, oxygen, form, grams, calculate. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. The full step-by-step solution to problem: 31P from chapter: 8 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Since the solution to 31P from 8 chapter was answered, more than 3008 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295.

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