Toilet bowl cleaners often contain hydrochloric acid to dissolve the calcium carbonate deposits that accumulate within a toilet bowl. How much calcium carbonate in grams can be dissolved by 5.8 g of HCl? (Hint: Begin by writing a balanced equation for the reaction between hydrochloric acid and calcium carbonate.)
Solution 82P
The balanced equation is,
CaCO3(s)+2HCl(aq)→CaCl2(aq)+H2O(l)+CO2(g)↑
Explanation:
The stoichiometrically balanced equation tells us that each equivalent calcium salt requires 2 equivalent hydrochloric acid for reaction to give soluble calcium chloride and carbon dioxide gas.
Moles of HCl = 5.8⋅g/36.46⋅g⋅mol−1= 0.159 mol.
And this will react with an equivalent mass of CaCO3,
here 0.159 mol 1/2
100.09 g/mol = 8.02g