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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 8 - Problem 82p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 8 - Problem 82p

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# Solved: Toilet bowl cleaners often contain hydrochloric acid to dissolve the calcium

ISBN: 9780321910295 34

## Solution for problem 82P Chapter 8

Introductory Chemistry | 5th Edition

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Problem 82P

Toilet bowl cleaners often contain hydrochloric acid to dissolve the calcium carbonate deposits that accumulate within a toilet bowl. How much calcium carbonate in grams can be dissolved by 5.8 g of HCl? (Hint: Begin by writing a balanced equation for the reaction between hydrochloric acid and calcium carbonate.)

Step-by-Step Solution:
Step 1 of 3

Solution 82P

The balanced equation is,

CaCO3(s)+2HCl(aq)→CaCl2(aq)+H2O(l)+CO2(g)↑

Explanation:

The stoichiometrically balanced equation tells us that each equivalent calcium salt requires 2 equivalent hydrochloric acid for reaction to give soluble calcium chloride and carbon dioxide gas.

Moles of HCl =  5.8⋅g/36.46⋅g⋅mol−1= 0.159 mol.

And this will react with an equivalent mass of CaCO3,

here 0.159 mol 1/2 100.09 g/mol = 8.02g

Step 2 of 3

Step 3 of 3

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