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Determine the electron and molecular geometries of each molecule.(a) N2O (oxygen is

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 69P Chapter 10

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 69P

Determine the electron and molecular geometries of each molecule.

(a) \(\mathrm{N}_{2} \mathrm{O}\) (oxygen is terminal)

(b) \(\mathrm{SO}_{2}\)

(c) \(H_{2} S\)

(d) \(P F_{3}\)

Equation Transcription:

Text Transcription:

N_2 O

SO_2

H_2 S

PF_3

Step-by-Step Solution:

Step 1 of 5

Here, we are going to find out electron and molecular geometries of each molecule.The bond angles can be calculated by using VSEPR theory. The repulsion between the electron groups of the internal atom determines the geometry of the molecule. The best possible geometry of the molecule is that where electron groups have maximum separation between them. The VSEPR notation for a molecule is as follows

 AXn, where "A" and n represents central atom and the number of bonds with the central atom respectively.

When lone pair of electrons are present in a molecule, then the VSEPR notation will be  AXnEn, where En is the number of lone pair of electrons present on the central atom.,

Electron group geometry depends on the number of electron groups around the central atom.

Molecular geometry of the molecule can be determined by electron groups as well lone pair of electrons.

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Step 2 of 5

Chapter 10, Problem 69P is Solved
Step 3 of 5

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Determine the electron and molecular geometries of each molecule.(a) N2O (oxygen is