Geometric sums Evaluate the following

Chapter 11, Problem 18E

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QUESTION:

7-18. Geometric sums Evaluate the following geometric sums.

\(\frac{1}{3}+\frac{1}{5}+\frac{3}{25}+\frac{9}{125}+\cdots+\frac{243}{15,625}\)

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QUESTION:

7-18. Geometric sums Evaluate the following geometric sums.

\(\frac{1}{3}+\frac{1}{5}+\frac{3}{25}+\frac{9}{125}+\cdots+\frac{243}{15,625}\)

ANSWER:

Problem 18EGeometric sums Evaluate the following geometric sums. Answer; Step-1; A sequence ( finite or infinite ) of non zero numbers is called a geometric progression ( abbreviated G.P) iff the ratio of any terms to its preceding term is constant . This non zero constant is usually denoted by ‘r’ and is called common ratio. General term of G.P is = a Thus , if ‘a’ is the first term and ‘r’ is the common ratio , then the G.P is a , ar , a,a………….according a

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